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3 years ago

A solution is made containing 4.92 g of sodium lithium chloride per 347 g of water.

Chemistry

1 answer:

Margaret [11]3 years ago

7 0

% mass of a solution is the mass of the solute present per 100 g of solution. It can be calculated using the formula,

$Mass % = \frac{Mass of solute (g)}{Mass of solution (g)} * 100$

Mass of solute = 4.92 g

Mass of solvent, water = 347 g

Total mass of solution = 347 g + 4.92 g = 351.92 g

Mass % of the solute = $\frac{4.92 g}{351.92 g} * 100 = 1.398 %$

Therefore, the weight/weight % = 1.398 %

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The stopcock connecting a 3.06 L bulb containing methane gas at a pressure of 9.61 atm, and a 6.65 L bulb containing oxygen gas

Contact [7]

Answer : The final pressure in the system is 4.22 atm.

Explanation :

First we have to calculate the moles of methane.

$PV=n_1RT$

where,

P = pressure of gas = 9.61 atm

V = volume of gas = 3.06 L

T = temperature of gas = T

$n_1$ = number of moles of methane gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$(9.61atm)\times (3.06L)=n_1\times RT$

$n_1=\frac{29.4}{RT}$

Now we have to calculate the moles of oxygen gas.

$PV=n_2RT$

where,

P = pressure of gas = 1.75 atm

V = volume of gas = 6.65 L

T = temperature of gas = T

$n_2$ = number of moles of oxygen gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$(1.75atm)\times (6.65L)=n_2\times RT$

$n_2=\frac{11.6}{RT}$

Now we have to determine the final pressure in the system after mixing the gases.

$P_{total}=(n_1+n_2)\times \frac{RT}{V_{total}}$

where,

$P_{total}$ = final pressure of gas = ?

$V_{total}$ = final volume of gas = (3.06 + 6.65)L = 9.71 L

T = temperature of gas = T

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$P_{total}=(\frac{29.4}{RT}+\frac{11.6}{RT})\times \frac{RT}{9.71L}$

$P_{total}=4.22atm$

Therefore, the final pressure in the system is 4.22 atm.

4 0

3 years ago

A solution has a pH of 2.5. what is the H+

romanna [79]

<u>Answer: </u>The concentration of $H^+$ in the solution is $3.16\times 10^{-3}M$

<u>Explanation:</u>

pH is defined as the negative logarithm of hydrogen ion concentration present in the solution.

$pH=-\log [H^+]$ .....(1)

We are given:

pH of solution = 2.5

Putting values in equation 1, we get:

$2.5=-\log [H^+]$

$[H^+]=10^{-2.5}$

$[H^+]=3.16\times 10^{-3}M$

Hence, the concentration of $H^+$ in the solution is $3.16\times 10^{-3}M$

4 0

3 years ago

Please HELP! Use the following Equations to answer the problem: CH3OH + O2 —> CO2 + H2O

snow_lady [41]

Answer:

The answer to your question is below

Explanation:

Balanced chemical reaction

2CH₃OH + 3O₂ ⇒ 2 CO₂ + 4H₂O

Reactant Element Product

2 C 2

8 H 8

8 O 8

Molar mass of CH₃OH = 2[12 + 16 + 4]

= 2[32]

= 64 g

Molar mass of O₂ = 3[16 x 2] = 96 g

Theoretical proportion CH₃OH/O₂ = 64 g/96g = 0.67

Experimental proportion CH₃OH/O₂ = 60/48 = 1.25

Conclusion

The limiting reactant is O₂ because the Experimental proportion was higher than the theoretical proportion

Balanced chemical reaction

S₈ + 12O₂ ⇒ 8SO₃

Reactant Elements Products

8 S 8

24 O 24

Molar mass of S₈ = 32 x 8 = 256 g

Molar mass of O₂ = 12 x 32 = 384 g

Theoretical proportion S₈ / O₂ = 256 / 384

= 0.67

Experimental proportion S₈ / O₂ = 40 / 35

= 1.14

Conclusion

The limiting reactant is O₂ because the experimental proportion was lower than the theoretical proportion.

6 0

4 years ago

Which of the following is not an essential element for healthy plant growth?

GREYUIT [131]

Answer:

A oxygen

Explanation:

For plant growth nitrogen, potassium and phosphorous are the three main elements needed. oxygen is expelled from plants. Plants doesn't need oxygen

8 0

3 years ago

Al(NO3)3+H2SO4=HNO3+Al2(SO4)3

bixtya [17]

Hey there!:

2 Al(NO)₃+ 3 H₂SO₄ → 1 Al₂O₁₂S₃+ 6 HNO₃

Reagents : Al(NO₃)₃ and H₂SO₄

Products : Al₂O₁₂S₃ and HNO₃

Coefficients : 2 , 3 , 1 and 6

Hope this helps!

3 0

3 years ago