I believe the answer is B
Hope it helped!
Answer: a) Partial pressure of argon is 0.673 atm.
b) Partial pressure of ethane is 0.427 atm.
Explanation:
According to the ideal gas equation:'
P = Pressure of the argon gas = ?
V= Volume of the gas = 1.00 L
T= Temperature of the gas = 25°C = 298 K (0°C = 273 K)
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas = 
Thus the partial pressure of argon is 0.673 atm.
b) According to Dalton's law, the total pressure is the sum of individual pressures.





Thus partial pressure of ethane is 0.427 atm.
First convert 12.0g of Na to moles using the grams to moles conversation and you get about .5219 moles (I didn't use significant figures). Divide that number by 3 because that is the coefficient of Na and you will get about .17398 moles, which is how many moles are in 1. Since Al has a coefficient of 1, .17398 woild be your final answer
Answer:
12.8 g of
must be withdrawn from tank
Explanation:
Let's assume
gas inside tank behaves ideally.
According to ideal gas equation- 
where P is pressure of
, V is volume of
, n is number of moles of
, R is gas constant and T is temperature in kelvin scale.
We can also write, 
Here V, T and R are constants.
So,
ratio will also be constant before and after removal of
from tank
Hence, 
Here,
and 
So, 
So, moles of
must be withdrawn = (0.66 - 0.26) mol = 0.40 mol
Molar mass of
= 32 g/mol
So, mass of
must be withdrawn = 