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harkovskaia [24]
3 years ago
11

Please help me out with this question

Mathematics
1 answer:
oee [108]3 years ago
4 0
The answer is B cause you add 6 and 2
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Find the solutions of the quadratic equation - 2^2+ 3x – 3 = 0
Assoli18 [71]

Answer:

-1/3

Step-by-step explanation:

2^2 + 3x - 3 = 0

4 - 3 + 3x = 0

1 + 3x = 0

x = -1/3

Hope it helps

7 0
2 years ago
Please solve!!!!!!!!!
Likurg_2 [28]

Answer:

A

Step-by-step explanation:

Plugging (t-2) in for x, you are left with:

f(t-2)=\sqrt{4(t-2)+1}=\\\sqrt{4t-8+1}=\\\sqrt{4t-7}or answer choice A. Hope this helps!

6 0
3 years ago
Suppose we have three urns, namely, A B and C. A has 3 black balls and 7 white balls. B has 7 black balls and 13 white balls. C
professor190 [17]

Answer:

a. 11/25

b. 11/25

Step-by-step explanation:

We proceed as follows;

From the question, we have the following information;

Three urns A, B and C contains ( 3 black balls 7 white balls), (7 black balls and 13 white balls) and (12 black balls and 8 white balls) respectively.

Now,

Since events of choosing urn A, B and C are denoted by Ai , i=1, 2, 3

Then , P(A1 + P(A2) +P(A3) =1 ....(1)

And P(A1):P(A2):P(A3) = 1: 2: 2 (given) ....(2)

Let P(A1) = x, then using equation (2)

P(A2) = 2x and P(A3) = 2x

(from the ratio given in the question)

Substituting these values in equation (1), we get

x+ 2x + 2x =1

Or 5x =1

Or x =1/5

So, P(A1) =x =1/5 , ....(3)

P(A2) = 2x= 2/5 and ....(4)

P(A3) = 2x= 2/5 ...(5)

Also urns A, B and C has total balls = 10, 20 , 20 respectively.

Now, if we choose one urn and then pick up 2 balls randomly then;

(a) Probability that the first ball is black

=P(A1)×P(Back ball from urn A) +P(A2)×P(Black ball from urn B) + P(A3)×P(Black ball from urn C)

= (1/5)×(3/10) + (2/5)×(7/20) + (2/5)×(12/20)

= (3/50) + (7/50) + (12/50)

=22/50

=11/25

(b) The Probability that the first ball is black given that the second ball is white is same as the probability that first ball is black (11/25). This is because the event of picking of first ball is independent of the event of picking of second ball.

Although the event picking of the second ball is dependent on the event of picking the first ball.

Hence, probability that the first ball is black given that the second ball is white is 11/25

​​

8 0
2 years ago
I need help with this
son4ous [18]
Hundreds: 7
tenths: 0
thousandths: 1

5 0
3 years ago
What is the image of the point (-1,-3)(−1,−3) after a rotation of 90 degrees counterclockwise about the origin?
ycow [4]

Answer:

(3,-1)

Step-by-step explanation:

6 0
3 years ago
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