3 years ago

Please please please help mess

Mathematics

1 answer:

Evgesh-ka [11]3 years ago

5 0

Answer:
what do you need help on?

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The entire question is un the picture

n200080 [17]

A) 6x -5y = 5
B) 3x + 5y = 4
Adding the equations:
9x = 9
x = 1

A) 6*1 -5y = 5
A) 6 - 5 = 5y
A) 5y = 1
y = 1/5 = .2

7 0

3 years ago

The shape of the top surface of a table is a trapezium. Find its area

qaws [65]

Answer:

0.88m²

Step-by-step explanation:

Area of a trapezium = 1/2(a+b)h

a and b are the parallel sides

h is the height

Given

a = 1m

b = 1.2m

h = 0.8m

Substitute

Area of the trapezium = 1/2(1+1.2)(0.8)

Area of the trapezium = 1/2(2.2)(0.8)

Area of the trapezium = 1.1 * 0.8

Area of the trapezium = 0.88m²

7 0

2 years ago

Zynga and Walmart which balance sheet items does the two have in common<br>

Nitella [24]

Need more context pls

6 0

2 years ago

Which is one of the solutions to the equation 2x^2 - x - 4 = 0

Alex73 [517]

Answer:

$x_{1}=\frac{1+\sqrt{33} }{4}\\x_{2}=\frac{1-\sqrt{33} }{4}$

Step-by-step explanation:

Using quadratic formula

$x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}$

we will have two solutions.

2x^2 - x - 4 = 0

So, a=2 b=-1 c=-4, we have:

$x_{1}=\frac{+1+\sqrt{-1^{2}-4*2*-4} }{2*2}\\\\x_{2}=\frac{+1-\sqrt{-1^{2}-4*2*-4} }{2*2}$

Finally, we have two solutions:

$x_{1}=\frac{1+\sqrt{33} }{4}\\\\x_{2}=\frac{1-\sqrt{33} }{4}$

5 0

3 years ago

Someone check my answers please

laiz [17]

Answer:

Thats good and its correct i think

Step-by-step explanation:

correct me

4 0

2 years ago

Read 2 more answers