Answer:
Option -c :5^ -12 . 2^ 40
Step-by-step explanation:
( 5^6 . 2^8 )( 5^-2 . 2^5 )
( 5^6 . 5^-2 ) ( 2^8 . 2^5 )
5^ -12 . 2^ 40
Option -c : 5^ -12 . 2^ 40
I hope im right!!
Answer:
Step-by-step explanation:
The total number of ways of selecting 3 gems of any kind without replacement is 35 * 34 * 33 = 39270
Now selecting 2 gems from 25 is 25C2
25 C 2 = 25 * 24/2 = 300
Selecting one good gem is 10
Total selection = 300 * 10 = 3000
P(gems) = 3000 / 39270
P(gems) = 300/3927
P(gems) = 100/1309
To answer this problem, the utilization of the provided formula is of utmost importance.
The formula to be used would be for the combination with no repetition since it is what is asked and possibly happens when involving the products mentioned in the problem. The formula would be
n! where in
------------- n = number of things to choose from
(n - r)! r! r = number of things needed to form
the symbol ! is called a factorial function which replaces the sequence of multiplying a number in a descending order.
lets substitute and solve
13!
--------------
(13 - 6)! 6!
13!
-------------
(7!) 6!
6,227,020,800
-------------------
5,040 x 720
6,227,020,800
-------------------
3,628,800
1,716
The answer would be 1,716.
The differences is 7 because I counted.
Answer:the quotient of 16 and x=4
Step-by-step explanation: