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PSYCHO15rus [73]
3 years ago
9

A piece of wood was thrown from the ship into the sea, with a thin rope attached to it. As the ship sailed on, the wood remained

bobbing in the water at about the same place; the rope unwound as the ship sailed by and away from the wood. By leaving the wood, or “log” as English sailors called it, in the water for a minute . . . the seaman would know how far the ship had traveled in that time, and so work out how far it had traveled in an hour. . . . [i]f a knot were tied in the rope every one-sixtieth of a mile, all a sailor had to do was to count the knots as he pulled in the rope, and he would know how many miles per hour his ship was traveling.”
How did tying knots in the rope make the job of figuring out how far a ship had traveled easier
Mathematics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

they would know because the rope will be one sixteenth of a mile and when the rope got maxed out in length it would show how far they have traveled and the wiould calculate how far they have been in that amount of time

Step-by-step explanation:

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ankoles [38]

Answer:

The trip normally takes 8 minutes

Step-by-step explanation:

The given information states that the away distance the boat traveled = 400 m

The time traveled at the same initial  speed , v₁, by the boat on the way back = 2 minutes

The increase in speed of the boat by Pilar =  10 m/min

The new speed, v₂ = v₁ + 10

The time for the return trip, t₂ = 60 seconds (1 minute) faster than time for the trip, t₁

t₂ = t₁ - 1

Therefore we have;

v₁ × t₁ = v₁×2 + v₂×(t₂-2) = 400

v₁×2 + (v₁ + 10)×(t₂-2) = 400

(v₁ + 10)×t₂ - 20 = 400

But v₁ = 400/t₁ = 400/(t₂ + 1)

Which gives;

(400/(t₂ + 1) + 10)×t₂ - 20 = 400

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MAXImum [283]

Answer:

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Step-by-step explanation:

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a + b = 130

We know the cost of Type A coffee is $5.20/lb and the cost of Type B coffee is $4.05/lb, so since the total cost is $586.30, we can write:

5.20a + 4.05b = 586.30

We can now solve the system of equations:

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Manipulate the first equation by subtracting b from both sides:

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