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PSYCHO15rus [73]
3 years ago
9

A piece of wood was thrown from the ship into the sea, with a thin rope attached to it. As the ship sailed on, the wood remained

bobbing in the water at about the same place; the rope unwound as the ship sailed by and away from the wood. By leaving the wood, or “log” as English sailors called it, in the water for a minute . . . the seaman would know how far the ship had traveled in that time, and so work out how far it had traveled in an hour. . . . [i]f a knot were tied in the rope every one-sixtieth of a mile, all a sailor had to do was to count the knots as he pulled in the rope, and he would know how many miles per hour his ship was traveling.”
How did tying knots in the rope make the job of figuring out how far a ship had traveled easier
Mathematics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

they would know because the rope will be one sixteenth of a mile and when the rope got maxed out in length it would show how far they have traveled and the wiould calculate how far they have been in that amount of time

Step-by-step explanation:

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Please help me on this i don’t get it that well
NeX [460]

Answer:

13.75

Step-by-step explanation:

make a ratio between the original lengths, 11 : 5.5

then put the ratio of the enlarged lengths, 27.5 : __

now you divide 27.5 by 11 to find how many times you multiplied the lengths, 2.5.

now you multiply 5.5 by 2.5 giving you the answer of 13.75

7 0
4 years ago
. A hawk flying at a height of 60 feet spots a rabbit on the ground. If the hawk dives at a speed of 55 feet per second, how
Vladimir [108]

Answer:

The hawk reaches the rabbit at t=4.3 sec

Step-by-step explanation:

Let

h ----> is the height in feet

t ----> is the time in seconds

v ---> the initial velocity in feet pr second

s ----- is the starting height

we have

h=-16t^{2} +vt+s

when the hawk reaches the rabbit the value of h is equal to zero

we have

v=55\ ft/sec

s=60\ ft

substitute

0=-16t^{2} +55t+60

Solve the quadratic equation by graphing

The solution is t=4.3 sec

see the attached figure

8 0
3 years ago
4{[5 (x-3)+2]-3 [2 (x+5)-9]}
Over [174]
Pemdas
parenthasees exponents mult/division additon/subtraction

parethenasees
x-3 and x+5 we can't do anything with so next
5(x-3)=5x-15

2(x+5)=2x+10

5x-15+2=5x-13

(2x+10-9)=2x+1

(5x-13)-3(2x+1)
-3(2x+1)=-6x-3

5x-13-6x-3=-x-16

4(-x-16)=-4x-64

the answer is -4x-64
6 0
4 years ago
Read 2 more answers
Which ones is the LCD (Least Common Denominator) out of these three number: 3, 4, and 20?
Verizon [17]
The least common denominator is 1.
4 0
3 years ago
Read 2 more answers
9mph in still water it takes 5hrs longer to travel 74 miles upstream than downstream find the rate of current and round to neare
prohojiy [21]

Answer:

The rate of current is 2.5 mph.

Step-by-step explanation:

The speed in the water when current is absent is 9 mph.

If the speed of the current is v mph then the upstream speed is (9 - v) mph and the downstream speed is (9 + v) mph.

Now, it takes 5 hours longer to travel 74 miles upstream than down stream, then we can write the equation as  

\frac{74}{9 - v} - \frac{74}{9 + v} = 5

⇒ \frac{2v}{81 - v^{2} } = \frac{5}{74}

⇒ 148v = 405 - 5v²

⇒ 5v² + 148v - 405 = 0

Applying Sridhar Acharya's formula we can write  

v = \frac{-148 + \sqrt{148^{2} - 4(5)(-405) }  }{2(5)} (Neglecting the negative root)

⇒ v = \frac{- 148 + 173.2166}{10} = 2.5 mph (Rounded to the nearest 10th) (Answer)

7 0
4 years ago
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