Given that Bill
is on the school archery team. the target has a center bull's-eye and
two rings around the bull's-eye.
Given the table below that gives the probabilities of outcomes.

The probability <span>that Bill will get the next arrow in the inner or outer ring is given by
P(inner ring) + P(outer ring) = 0.297 + 0.423 = 0.72</span>
Therefore, <span>the probability that Bill will get the next arrow in the inner or outer ring is 0.72</span>
Answer: 4
Step-by-step explanation:
The two angles are 155 degrees and 25 degrees
<h3><u>
Solution:</u></h3>
Given that two supplementary angles are in ratio 31 : 5
Let the first angle be 31a
Let the second angle be 5a
Two Angles are Supplementary when they add up to 180 degrees.
Therefore,
first angle + second angle = 180 degrees

<em><u>Therefore the angles are:</u></em>
first angle = 31a = 31(5) = 155 degrees
second angle = 5a = 5(5) = 25 degrees
Thus the two angles are 155 degrees and 25 degrees
Answer:
cot∅ = (-2√30)/7.
Step-by-step explanation:
Given the value of csc∅ = -13/7 and ∅ is in quad III.
We know y = r sin∅ and r > 0. So csc∅ = r/y = -13/7 = 13/(-7).
It means y = -7, r = 13.
We know x² + y² = r².
x² = r² - y²
x² = (13)² - (-7)² = 169 - 49 = 120.
x = √120 = 2√30.
we know cot∅ = x/y = (2√30)/(-7) = (-2√30)/7.
Hence, cot∅ = (-2√30)/7.