Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
330 page/(3/4 Hour):==> 330 : 3/4
To solve this division you have to MULTIPLY the 1st term by the reciprocal of the 2nd (the reciprocal of 3/4 is 4/3), so
330 x 4/3 = (330x4)/3 = 440
330 pages were read in 3/4 Hour (given) & in 1 hour. could be read
Step-by-step explanation:
given x=2
and the equation
to find the value of q , you need to make q the subject in the equation as shown below
q= 3x-x -4
q=2x-4
but x= 2
so just substitute the value of x in the equation for the q
q=4-4
q=0
therefore the value of q is 0
Answer:
A. 102,198 employees
B. $22,120 decrease
$293,880 current value
Step-by-step explanation:
