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alexandr1967 [171]

3 years ago

6

Magnesium has three naturally occurring isotopes with masses of 23.99 amu, 24.99 amu, and 25.98 amu and natural abundances of 78

.99%, 10.00% and 11.01% respectively. How do you calculate the atomic mass of magnesium?

1 answer:

mihalych1998 [28]3 years ago

3 0

Answer:24.31

Explanation:Contribution made by isotope of mass 23.99= 23.99×78.99=1894.97

Contribution made by isotope of mass 24.99=24.99×10.00=249.9

Contribution made by isotope of mass 25.98=25.98×11.01=286.04

Total contribution=1894.97+249.9+286.04=2430.91

Average mass=2430.91÷100

=24.31

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3 years ago

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What is the word that means "these break food into pieces

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Your digestive system

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3 years ago

Perform the following unit conversions:

Y_Kistochka [10]

Answer :

(a) The 60 feet of water is equal to 179344.2 Pa.

(b) The 220 psi is equal to $31680lbf/ft^2$

(c) The 120 torr is equal to 15998.6 Pa.

(d) The 1.0 atm to inches of glycerin is equal to 323.07 inches.

(e) The 1050 mm Hg is equal to $376.95lbf/ft^2$

Explanation :

(a) The conversion used from feet to pascal is:

$1\text{ feet}=2989.07Pa$

As we are given that 60 feet of water. Now we have to convert into Pa.

As, $1\text{ feet}=2989.07Pa$

So, $60\text{ feet}=\frac{60\text{ feet}}{1\text{ feet}}\times 2989.07Pa=179344.2Pa$

The 60 feet of water is equal to 179344.2 Pa.

(b) The conversion used from $psi$ to $lbf/ft^2$ is:

$1\text{ psi}=144lbf/ft^2$

As we are given that 220 psi. Now we have to convert into $lbf/ft^2$ .

As, $1\text{ psi}=144lbf/ft^2$

So, $220\text{ psi}=\frac{220\text{ psi}}{1\text{ psi}}\times 144lbf/ft^2=31680lbf/ft^2$

The 220 psi is equal to $31680lbf/ft^2$

(c) The conversion used from torr to pascal is:

$1\text{ torr}=133.322Pa$

As we are given that 120 torr. Now we have to convert into Pa.

As, $1\text{ torr}=133.322Pa$

So, $120\text{ torr}=\frac{120\text{ torr}}{1\text{ torr}}\times 133.322Pa=15998.6Pa$

The 120 torr is equal to 15998.6 Pa.

(d) 1.0 atm to inches of glycerin

Formula used : $P=\rho gh$

where,

P = pressure of glycerin = 1.0 atm = 101325 Pa

g = acceleration due to gravity = $9.8m/s^2$

$\rho$ = density of glycerin = $1260kg/m^3$

Now put all the given values in above formula, we get:

$101325Pa=(1260kg/m^3)\times (9.8m/s^2)\times h$

$h=8.206\frac{Pa.m^2s^2}{kg}=8.206m=323.07\text{ inches}$

Conversion used :

$1Pa=\frac{kg}{ms^2}\\\\1m=39.37inches$

The 1.0 atm to inches of glycerin is equal to 323.07 inches.

(e) The conversion used from $psi$ to $lbf/ft^2$ is:

$1\text{ mmHg}=0.359lbf/ft^2$

As we are given that 1050 mmHg. Now we have to convert into $lbf/ft^2$ .

As, $1\text{ mmHg}=0.359lbf/ft^2$

So, $1050\text{ mmHg}=\frac{1050\text{ mmHg}}{1\text{ mmHg}}\times 0.359lbf/ft^2=376.95lbf/ft^2$

The 1050 mm Hg is equal to $376.95lbf/ft^2$

4 0

3 years ago

Mercury and its compounds have uses from fillings for teeth (as a mixture with silver, copper, and tin) to the production of chl

Y_Kistochka [10]

Answer:

0.6410g of HgS (mercury (II) sulfide) are formed

Explanation:

First you should write the balanced chemical equation, so we have:

$Na_{2}S+Hg(NO_{3})_{2}=HgS+_{2}NaNO_{3}$

Where:

$Na_{2}S$ is the formula for the sodium sulfide

$Hg(NO_{3})_{2}$ is the formula for the mercury (II) nitrate

$HgS$ is the formula for the mercury (II) sulfide

and

$NaNO_{3}$ is the formula for the sodium nitrate

Then you should calculate the amount of each substance in each solution, so:

- For the $Na_{2}S$ :

$Molarity=\frac{n_{Na_{2}S}}{Lofsolution}$

$n_{Na_{2}S}=0.048M*0.236L$

$n_{Na_{2}S}=0.010856$ moles of $Na_{2}S$

- For the $Hg(NO_{3})_{2}$ :

$Molarity=\frac{n_{Hg(NO_{3})_{2}}}{Lofsolution}$

$n_{Hg(NO_{3})_{2}}=0.019M*0.145L$

$n_{Hg(NO_{3})_{2}}=0.002755$ moles of $Na_{2}S$

As the quantity of $Hg(NO_{3})_{2}$ is smaller than the quantity of $Na_{2}S$ . The $Hg(NO_{3})_{2}$ is the limiting reagent and you should work with this quantity, so we have:

$0.002755molesHg(NO_{3})_{2}*\frac{1molHgS}{1molHg(NO_{3})_{2}}=0.002755$ moles of HgS

And as the molar mass of the HgS is $232.66\frac{g}{mol}$ you can calculate the mass of HgS that is produced:

$0.002755molesHgS*\frac{232.66gHgS}{1molHgS}=0.6410g$ HgS

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3 years ago

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3 years ago

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