If the percent transmittance is is 64.9 in 0.2M standard CuSO4, what is the absorption?

Calculate the unit cell edge length for an 85 wt% fe-15 wt% v alloy. All of the vanadium is in solid solution, and, at room temp

Lady bird [3.3K]

Answer is 0.289nm.

Explanation: The wt % of Fe and wt % of V is given for a Fe-V alloy.

wt % of Fe in Fe-V alloy = 85%

wt % of V in Fe-V alloy = 15%

We need to calculate edge length of the unit cell having bcc structure.

Using density formula,

$\rho_{ave}=\frac{Z\times M_{ave}}{a^3\times N_A}$

For calculating edge length,

$a=(\frac{Z\times M_{ave}}{\rho_{ave}\times N_A})^{1/3}$

For calculating $M_{ave}$ , we use the formula

$M_{ave}= \frac{100}{\frac{(wt\%)_{Fe}}{M_{Fe}}+\frac{(wt\%)_{V}}{M_V}}$

Similarly for calculating $(\rho)_{ave}$ , we use the formula

$\rho_{ave}= \frac{100}{\frac{(wt\%)_{Fe}}{\rho_{Fe}}+\frac{(wt\%)_{V}}{\rho_V}}$

From the periodic table, masses of the two elements can be written

$M_{Fe}= 55.85g/mol$

$M_{V}=50.941g/mol$

Specific density of both the elements are

$(\rho)_{Fe}=7.874g/cm^3\\(\rho)_{V}=6.10g/cm^3$

Putting $M_{ave}$ and $\rho_{ave}$ formula's in edge length formula, we get

$a=\left [\frac{Z\left (\frac{100}{\frac{(wt\%)_{Fe}}{M_{Fe}}+\frac{(wt\%)_{Fe}}{M_{Fe}}} \right )}{N_A\left (\frac{100}{\frac{(wt\%)_V}{\rho_V}+\frac{(wt\%)_V}{\rho_V}} \right )} \right ]^{1/3}$

$a=\left [\frac{2atoms/\text{unit cell}\left (\frac{100}{\frac{85\%}{55.85g/mol}+\frac{15\%}{50.941g/mol}} \right )}{(6.023\times10^{23}atoms/mol)\left (\frac{100}{\frac{85\%}{7.874g/cm^3}+\frac{15\%}{6.10g/cm^3}} \right )} \right ]^{1/3}$

By calculating, we get

$a=2.89\times10^{-8}cm=0.289nm$

7 0

3 years ago

What is a niche of a greenfly?

gizmo_the_mogwai [7]

Answer:

Explanation:

Different butterfly species occupy slightly different niches, but most are forest- or field-dwelling, flying, nectar-feeding insects. ... During feeding, butterflies are often covered in pollen, making them effective agents of pollination for plants.

3 0

3 years ago

Where does cellular respiration

Svetradugi [14.3K]

Answer:

Number 2

Explanation:

3 0

3 years ago

Read 2 more answers

Many tests to distinguish aldehydes and ketones involve the addition of an oxidant. Only __________ can be easily oxidized becau

tatiyna

Answer:

Aldehydes
A hydrogen atom
Oxygen

Explanation:

Many tests to distinguish aldehydes and ketones involve the addition of an oxidant. Only <u>aldehydes</u> can be easily oxidized because there is<u> a hydrogen atom</u> next to the carbonyl and oxidation does not require<u> oxygen </u>

4 0

3 years ago

what is the molecular formula of a compound that contains 38% c, 45% n and 16% h if 0.157 g of the compound occupies 125 ml with

EastWind [94]

The molecular formula of the given compound is CH₅N.

<h3>What is the ideal gas equation?</h3>

The ideal gas law has defined the product of the volume and pressure as equal to the product of the gas constant (R) and absolute temperature of the gas.

The mathematical equation of the ideal gas law is as follows:

PV = nRT

The temperature of the compound, T = 22° C = 295 K

The pressure of the compound, P = 99.5 KPa = 0.982 atm

The volume of the compound, V = 125 ml = 0.125 L

0.125 × 0.982 = (0.157 g/M) × 0.082 ×295

M = 31 g/mol

A number of moles of C = 0.157 ×0.37/12 = 0.00484

A number of moles of N = 0.157 ×0.45/14 = 0.00504

A number of moles of H = 0.157 ×0.16/1 = 0.0251

The simplest ratio of C: N: H is 1 : 1 : 5

The empirical formula of the given compound is CH₅N.

The molecular formula of the compound is CH₅N as the molecular mass is equal to 31 g/mol.

Learn more about ideal gas equation, here:

brainly.com/question/3637553

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4 0

1 year ago