If 279 grams of iron react with an excess of oxygen, as shown in the balanced equation below, how many grams of iron (iii) oxide
1 answer:
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<u>Answer:</u> The volume of barium hydroxide is 183 mL.
<u>Explanation:</u>
To calculate the moles of cadmium nitrate, we use the equation:
.....(1)
Molarity of = 0.796 M
Volume of = 161 mL = 0.161 L (Conversion factor: 1 L = 1000 mL)
Putting values in equation 1, we get:
The chemical equation for the reaction of manganese sulfate and barium hydroxide follows:
By Stoichiometry of the reaction:
1 mole of manganese sulfate reacts with 1 mole of barium hydroxide.
So, 0.13 moles of manganese sulfate will react with = of barium hydroxide
Now, calculating the volume of barium hydroxide by using equation 1, we get:
Moles of barium hydroxide = 0.13 moles
Molarity of barium hydroxide = 0.710 M
Putting values in equation 1, we get:
Converting this into milliliters, we use the conversion factor:
1 L = 1000 mL
So,
Hence, the volume of barium hydroxide is 183 mL.
Answer: The ratio of carbon dioxide molecules to oxygen molecules is 20 :31
Explanation:
Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced combustion reaction is,:
Thus the ratio of carbon dioxide molecules to oxygen molecules is 20 : 31