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Fittoniya [83]
3 years ago
13

If 279 grams of iron react with an excess of oxygen, as shown in the balanced equation below, how many grams of iron (iii) oxide

can be formed? 4fe + 3o2 yields 2fe2o3 139.5 grams 199.5 grams 399 grams 1596 grams
Chemistry
1 answer:
dsp733 years ago
8 0

Answer:-

399 gram

Explanation:-

The balanced chemical equation for the reaction is

4Fe +3 O2 --> 2 Fe2O3

Atomic mass of Iron Fe is 55.845 gram

Molecular mass of Iron (III) Oxide Fe2O3 is

55.845 x 2 + 16 x 3 = 159.69 gram

From the balanced chemical equation,

4 Fe gives 2 Iron (III) oxide

∴ 4 x 55.845 grams of Fe gives 2 x 159.69 grams of Iron (III) Oxide.

279 grams of Fe gives (2 x 159.69) x 279 / ( 4 x 55.845)

= 399 gram

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