The volume is 2.23 liters of hydrogen gas.
<u>Explanation</u>:
moles of C = grams / molecular mass of C
= 1.04 g / 12.011 g/mol.
= 0.086
The ratio between C and H2 is 1 : 1
moles H2 = 0.086
V = nRT / p
= 0.086 x 0.08206 x 316 K / 1.0 atm
V = 2.23 L.
Soil
profile
Soil
profile is the vertical sequence of the layers of soil. Furthermore, there are
actually six layers of the soil which involves the organic matter, -where most
humus is present-, surface soil, the subsoil, the parent rock, and the bedrock
as the innermost and core layer of the soil. In addition each soil layer has
three to four soil horizon. These horizons are the physical features of the soil,
mainly the texture, color and composition.
Answer:
D
Excess solar radiation due to a missing magnetic field.
Explanation: Solar proton events (SPEs) are bursts of energetic protons accelerated by the Sun. They occur relatively rarely and can produce extremely high radiation levels. Without thick shielding, SPEs are sufficiently strong to cause acute radiation poisoning and death.
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Answer:
1. C4H8 + 6O2 -----> 4CO2 + 4H20
2. 3836.77 kcal
Explanation:
1. Balanced equation for the complete combustion of cyclobutane:
C4H8 + 6O2 -----> 4CO2 + 4H20
2. Heat of combustion of cyclobutane = 650.3 kcal/mol
Molecular weight of cyclobutane, C4H8 = 56.1 g/mol
Mole of C4H8 : mass of cyclobutane/Molecular weight of cyclobutane
Mole of C4H8 = 331/56.1 = 5.9 mol
Energy released during combustion = 5.9 mol × 650.3 kcal/mol = 3836.77kcal
Therefore the energythat is released during the complete combustion of 331 grams of cyclobutane is 3836.77kcal
