Let's buils the intersection plane:
Point P is on AB and AP=2, then PB=3; point Q is on AE and AQ=1, then QE=4. Let P' be a point on CD such that CP'=2 and Q' be a point on the plane CDHG such that P'Q'=1 and P'Q' is perpendicular to CD. The line CQ' intersects HD at point R and the plane CPQR is intersection plane.
Consider triangles ΔCDR and ΔCP'Q', they are similar. So,
,
so R is a midlepoint of the side HD (for details see picture).
Answer:
Image 1
Step-by-step explanation:
To answer this question, we need to know how to use a box plot.
I've attached an image that demonstrates this well and can teach you what each part of the box plot means.
Specifically, the 2 farthest dots at the end are the minimum and maximum. The two sides where the box starts are the lower and upper quartiles. Finally, the line in the middle of the box is the median.
With this, we can analyze each box plot and determine which one is correct.
<em><u>Box Plot 1: </u></em><em>Everything is plotted correctly- Maximum and minimum plotted correctly, median plotted correctly, upper and lower quartile plotted correctly.</em>
<u>Box Plot 2:</u> Everything plotted correctly EXCEPT maximum of 48 is represented at 46.
<u>Box Plot 3:</u> Everything plotted correctly EXCEPT the upper quartile of 45 is at 39.
<u>Box Plot 4:</u> Upper quartile represented at 39 and maximum represented at 46 are both incorrect.
In a function, every point is mapped to at most one other point. B is the answer.
In A, -1 maps to 2 points.
In C, 3 maps to 2 points.
In D, 2 maps to 2 points.
So they are not functions.
Answer:
21
Step-by-step explanation:
Answer:
x = 30°
Step-by-step explanation:
the small triangle is equilateral
That means that side with angle x that shares the same side with the other triangle is also 40
so its isosceles
in the equilateral, all angles measure 60
so 180 -60 = 120
180 - 120 = 60
60/2 = 30