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julia-pushkina [17]
3 years ago
8

Can someone help me please, explain in your own words. I'll give brainliest to the best and correct answer. Thank you (:

Mathematics
1 answer:
Elanso [62]3 years ago
6 0
A) To factor a quadratic equation, standard form is the better form to use because it is easier to pull out a common factor from. 

b) To graph a parabola, it is better to use vertex form so that you will know what point to graph as the vertex of the parabola. 

c) To identify the vertex, maximum and minimum, it is better to use vertex form because the vertex form will give the values of the coordinates for the vertex. Then, you can use the equation to find the mininmum or maximum. If the graph is negative, it will have a maximum because it points downward infinitely. If the equation is positive, the graph will have a minimum because the graph points upward infinitely.

d) Standard form is easier to use when trying to solve using the quadratic formula because  it is easier to see what the coeffiecnts and constants are to plug in for a b and c. 
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What is 5.72 × 10^3 in standard form?
iVinArrow [24]

Answer: 5,720

Step-by-step explanation: The number shown here 5.72 × 10³ is written in scientific notation since it's composed of a decimal between 1 and 10 in this case 5.72 and a power of 10 in this case 10³. To write 5.72 × 10³ in standard notation, we first begin with 5.72.

Next, we look at the exponent which in this case is positive 3. The exponent tells us to move the decimal point three places to the right.

Finally, we fill in the missing positions with zeros.

Therefore, 5.72 × 10³ written in standard notation is 5,720.

6 0
3 years ago
The price of a video game is $35.60. if you purchase the video game for $30.26 with a coupon, what percent of the original price
prohojiy [21]
35.60-30.26=5.34. 5.34=13%
3 0
3 years ago
The function h(x) is defined as shown.
Ierofanga [76]

9514 1404 393

Answer:

  (b)  h(x) ≤ 5

Step-by-step explanation:

The maximum vertical extent of the graph is h(x) = 5 at x = 3. The range is all values of h(x) less than or equal to that:

  h(x) ≤ 5

3 0
3 years ago
Read 2 more answers
Find the perimeter and the area of the figure.
Gwar [14]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

<u>the </u><u>given </u><u>figure </u><u>is </u><u>a </u><u>composition</u><u> </u><u>of </u><u>a </u><u>rectangle</u><u> </u><u>as </u><u>well </u><u>as </u><u>a </u><u>right </u><u>angled </u><u>triangle </u><u>!</u>

<u>we've</u><u> </u><u>been </u><u>given </u><u>the </u><u>two </u><u>sides </u><u>of </u><u>the </u><u>rectangle </u><u>and </u><u>we're</u><u> </u><u>required</u><u> </u><u>to </u><u>find </u><u>out </u><u>the </u><u>height </u><u>of </u><u>the </u><u>triangle </u><u>,</u><u> </u><u>so </u><u>as </u><u>to </u><u>find </u><u>it's</u><u> </u><u>area </u><u>~</u>

<u>we </u><u>know </u><u>the </u><u>the </u><u>opposite</u><u> </u><u>sides </u><u>of </u><u>a </u><u>rectangle </u><u>are </u><u>equal</u><u> </u><u>,</u><u> </u><u>therefore </u><u>we </u><u>can </u><u>break </u><u>the </u><u>longest </u><u>side </u><u>(</u><u> </u><u>length </u><u>=</u><u> </u><u>9</u><u>.</u><u>5</u><u> </u><u>cm </u><u>)</u><u> </u><u>into </u><u>two </u><u>parts </u><u>!</u><u> </u><u>the </u><u>first </u><u>part </u><u>of </u><u>length </u><u>=</u><u> </u><u>7</u><u> </u><u>cm </u><u>which </u><u>is </u><u>the </u><u>length </u><u>of </u><u>the </u><u>rectangle </u><u>and </u><u>the </u><u>rest </u><u>2</u><u>.</u><u>5</u><u> </u><u>cm </u><u>(</u><u> </u><u>9</u><u>.</u><u>5</u><u> </u><u>-</u><u> </u><u>7</u><u> </u><u>=</u><u> </u><u>2</u><u>.</u><u>5</u><u> </u><u>)</u><u> </u><u>will </u><u>become </u><u>the </u><u>height </u><u>of </u><u>the </u><u>triangle </u><u>!</u>

<h3><u>For </u><u>perimeter</u><u> </u><u>of </u><u>the </u><u>figure </u><u>-</u></h3>

perimeter \: of \: figure = perimeter \: of \: rectangle + perimeter \: of \: triangle \\  \\

now ,

<u>perimeter</u><u> </u><u>of </u><u>rectangle </u><u>=</u><u> </u><u>2</u><u> </u><u>(</u><u> </u><u>l </u><u>+</u><u> </u><u>b </u><u>)</u>

where ,

<u>l </u><u>=</u><u> </u><u>length </u>

<u>b </u><u>=</u><u> </u><u>breadth </u>

\longrightarrow \: perimeter = 2(7 + 6) \\ \longrightarrow \: 2(13) \\ \longrightarrow \: 26 \: cm

and ,

perimeter \: of \: \triangle = 6.5 + 2.5 + 6 \\ \longrightarrow \: 15 \: cm

<u>Perimeter</u><u> </u><u>of </u><u>figure </u><u>in </u><u>total </u><u>=</u><u> </u><u>2</u><u>6</u><u> </u><u>cm </u><u>+</u><u> </u><u>1</u><u>5</u><u> </u><u>cm</u>

thus ,

\qquad\quad\bold\red{perimeter \: = \: 41 \: cm}

<h3><u>For </u><u>area </u><u>of </u><u>the </u><u>figure </u><u>-</u></h3>

area \: of \: figure = area \: of \: rectangle  + area \: of \: rectangle \\

now ,

<u>area </u><u>of </u><u>rectangle</u><u> </u><u>=</u><u> </u><u>l </u><u>×</u><u> </u><u>b</u>

where ,

<u>l </u><u>=</u><u> </u><u>length </u>

<u>b </u><u>=</u><u> </u><u>breadth</u>

area \: of \: rectangle = 7 \times 6 \\ \longrightarrow \: 42 \: cm {}^{2}

and ,

area \: of\triangle =  \frac{1}{2}  \times base \times height \\  \\ \longrightarrow \:   \frac{1}{\cancel2}  \times \cancel6 \times 2.5 \\  \\ \longrightarrow \: 3 \times 2.5 \\  \\ \longrightarrow \: 7.5 \: cm {}^{2}

<u>Area </u><u>of </u><u>figure</u><u> </u><u>in </u><u>total </u><u>=</u><u> </u><u>4</u><u>2</u><u> </u><u>cm²</u><u> </u><u>+</u><u> </u><u>7</u><u>.</u><u>5</u><u> </u><u>cm²</u>

thus ,

\qquad\quad\bold\red{Area \: = \: 49.5 \: cm^{2}}

hope helpful :)

6 0
1 year ago
Read 2 more answers
Can anyone please make up some easy questions for me to do? I need at least five
KatRina [158]

Answer:

well ig thats good

Step-by-step explanation:

thanks

5 0
2 years ago
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