Answer:
55, 125 and 125
Step-by-step explanation:
In this question, we are asked to find the other 3 angles in an intersection.
Please check attachment for what the diagram of the intersection might look like.
The intersection consists simply of 4 angles meeting at a point with the 2 angles on each side vertically opposite to the angles on the other side.
since one of the angles is 55, and we are having a straight line, the other angle would be 180-55 = 125.[ sum of angles on a straight line is 180]
These two angles are vertically opposite, this means that the other three angles are 55,125 and 125.
-3/4x + 5/6 y = 15
Multiply through by 6
-9/2x + 5y = 90
Add 9/2x to both sides
5y = 90 + 9/2x
Divide both sides by 5
y = 18 + 9/10x
y = 9/10x + 18
Comparing with the general equation of a straight line y = mx + c
Gradient (m) = 9/10 or 0.9
and the y - intercept (c) = 18
Yes, because it is continuous on [0,2] and differentiable on (0,2), the theorem states that there must exist some value c where a line tangent to c is parallel to the secant line through 0 and 2.
Step-by-step explanation:
multiply it
x²-3x+3x-9=0
x²-9=0
x²=9
square root both side we get
x=3
The answer is 170. First you add base one and base two divide by twi the multiply that by the height. 18+22=40 40/2=20 20•8.5=170