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3 years ago

A pair of socks is purchased

Mathematics

2 answers:

ycow [4]3 years ago

8 0

There was a 200% increase

Leokris [45]3 years ago

3 0

It is a 100% increase

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Divde 3/4÷5/7 what was the error 5/7÷3/4=5/7*4/3=20/21

Setler79 [48]

instead of changing the 5/7 u change the 3/4

7 0

3 years ago

Number of solutions to a system of equations algebraic. How many solutions does the system have? Can someone help me please....

Svet_ta [14]

Answer:

A Exactly 1 solution

Step-by-step explanation:

if we express both equations as y = mx+b

we will see that both equations have different slopes (i.e "m" values are different).

By definition, 2 straight lines of different slopes will intersect at only one location (i.e there is only one solution)

8 0

3 years ago

Read 2 more answers

What is an equation of the line that passes through the points (6, -1) and (1, 4)?

Nataly [62]

Here you go! Hope this helps!

3 0

1 year ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

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2 years ago

What does a negative plus a negative number equal? What does a negative plus a negative number equal? 1 following 10 answers 10

Georgia [21]

It will equal a negative sum

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3 years ago