Answer:
480 times
Step-by-step explanation:
Given
---- total number of rolls
See attachment for complete question
Required
Times OO will appear in a roll of 2000 times
From the attached bar graph,

So, the occurrence of OO in 2000 rolls is:




You can solve for it, i believe, using the following formula
[(new-old)/old]*100
OR
(AmtIncreased/OriginalAmt)*100
You can set up a proportion like
"scale for inches" : "scale for feet" = "actual inches" : "actual feet"
Plugging the numbers, you have

Now, you can either solve this proportion by x, or simply realize that you can start from the "2 inches = 55 feet" scale, and multiply both sides by 11 to get that 22 inches are
feet.
Answer:
-m^12
Step-by-step explanation: