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AveGali [126]
3 years ago
9

Select the correct answer.

Mathematics
1 answer:
Darya [45]3 years ago
5 0
C. 81.74 ............
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Please help fast......
Tom [10]

3)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\ 1.AY=BX&\text{1. Given}\\ 2.AB \cong AB&\text{2. Reflexive Property}\\ 3. AD || BC&\text{3. Property of a square}\\ 4. \angle ABE \cong \angle AXB&\text{4. Alternate Interior Angles}\\ 5. \angle BAY \cong \angle BYA&\text{5. Alternate Interior Angles}\\6. \triangle BAX \cong \triangle ABY&\text{6. Angle-Side-Angle Theorem}\\ 7. AX \cong BY&\text{7. CPCTC}\\\end{array}

*************************************************************************************

6)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\1. AB=CF&\text{1. Given}\\2.AB+BF=A'F&\text{2. Segment Addition Postulate}\\3.CF+BF=A'F&\text{3. Substitution Property}\\4.CF+BF+BC&\text{4. Segment Addition Postulate}\\5.A'F=BC&\text{5. Transitive Property}\\6. \angle AFE = \angle DBC&\text{6. Given}\\7. EF = BD&\text{7. Given}\\8. \triangle AFE \cong \triangle CBD&\text{8. Side-Angle-Side Theorem}\\\end{array}

*************************************************************************************

7)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\\text{1.AC bisects }\angle BAD&\text{1. Given}\\2. \angle BAC \cong \angle DAC&\text{2. Property of angle bisector}\\3.AC = AC&\text{3. Reflexive Property}&4. \angle ACB \cong \angle ACD&\text{4. Property of angle bisector}\\5. \triangle ABC \cong \triangle ADC&\text{5. Angle-Side-Angle Theorem}\\6.BC=CD&\text{6. CPCTC}\\\end{array}

5 0
3 years ago
Write an equation for a line parallel to y=3x-3 and passing through the point (4,15)
Andrews [41]

Hello!

To find the equation of a line parallel to y = 3x - 3 and passing through the point (4, 15), we need to know that if two lines are parallel, then their slopes are equivalent.

This means that we create a new equation in slope-intercept form, which includes the original slope, which is equal to 3.

In slope-intercept form, we need a y-intercept. So, we would substitute the given ordered pair into the new equation with the same slope and solve.

Remember that slope-intercept form is: y = mx + b, where m is the slope and b is the y-intercept.

y = 3x + b (substitute the ordered pair (4, 15))

15 = 3(4) + b (simplify)

15 = 12 + b (subtract 12 from both sides)

3 = b

Therefore, the equation for the line parallel to the line y = 3x - 3, and passing through the point (4, 15) is y = 3x + 3.

8 0
3 years ago
Cody was
frutty [35]
On the first day of school last year, Cody was 148.5 cm tall.
5 0
3 years ago
Please help me with these two i have to send it after class!!!!!
scoundrel [369]

the first one is the answer to #1

and the second one is the answer to #2

5 0
3 years ago
100 POINTS!!!!!! the following stem and leaf plot shows the number of hours that mrs. dixon's students spent on their pre calc w
mylen [45]

Answer:

11.2467

Step-by-step explanation:

First we need to find the mean

Add up all the data and divide by number of points)

(6+7+8+10+12+13+14+17+17+17+18+19+21+23+24+24+25+27+31+31+32+36+36+39+41+45+45+46+49+50)/30

261/10

26.1

Then to find the mean absolute deviation take each value and find the absolute value from the mean and sum it and then divide by the number of points

((26.1 -6)+(26.1-7)+(26.1-8)+(26.1-10)+(26.1-12)+(26.1-13)+(26.1-14)+(26.1-17)+(26.1-17)+(26.1-17)+(26.1-18)+(26.1-19)+(26.1-21)+(26.1-23)+(26.1-24)+(26.1-24)+(26.1-25)+(27-26.1)+(31-26.1)+(31-26.1)+(32-26.1)+(36-26.1)+(36-26.1)+(39-26.1)+(41-26.1)+(45-26.1)+(45-26.1)+(46-26.1)+(49-26.1)+(50-26.1))/30

11.2467

5 0
3 years ago
Read 2 more answers
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