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anyanavicka [17]
3 years ago
5

A house has increased in value by 29% since it was purchased. If the current value is $516,000, what was the value when it was p

urchased?
Mathematics
2 answers:
Troyanec [42]3 years ago
4 0

X=value of the house before increase

(100%+29%)X=516,000

(129%)X=516,000

1.29x=516,000 | divided by 1.29 both sides

X=400,000$ was the value when it was purchased

kotegsom [21]3 years ago
3 0

Answer:

The value of house $ 400,000

Step-by-step explanation:

Let x be the price of house when it was purchased,

∵ 29% of x = \frac{29x}{100} = 0.29x

According to the question,

x + 29% of x = 516000

x + 0.29x = 516000

1.29x = 516000

\implies x=\frac{516000}{1.29}=400000

Hence, the value of the house is $ 400,000 when it was purchased.

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