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anyanavicka [17]
3 years ago
5

A house has increased in value by 29% since it was purchased. If the current value is $516,000, what was the value when it was p

urchased?
Mathematics
2 answers:
Troyanec [42]3 years ago
4 0

X=value of the house before increase

(100%+29%)X=516,000

(129%)X=516,000

1.29x=516,000 | divided by 1.29 both sides

X=400,000$ was the value when it was purchased

kotegsom [21]3 years ago
3 0

Answer:

The value of house $ 400,000

Step-by-step explanation:

Let x be the price of house when it was purchased,

∵ 29% of x = \frac{29x}{100} = 0.29x

According to the question,

x + 29% of x = 516000

x + 0.29x = 516000

1.29x = 516000

\implies x=\frac{516000}{1.29}=400000

Hence, the value of the house is $ 400,000 when it was purchased.

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Answer:  7\frac{5}{7} unit and 18 unit

Step-by-step explanation:

Let ABCD is a trapezoid where AB and CD are the bases. ( In which AB is greatest base which shown in below figure)

AD and BC are the legs of the trapezoid ABCD.

Now, we have ( According to the question ),

AB = 18 unit, BC = 7 unit, AD = 3 unit and DC = 11 unit.

Here the leg AD extends from point D.

Similarly leg BC extends from point C.

Let they meet at point P ( shown in below diagram)

Since In triangles PAB and PDC,

∠PDC ≅ ∠PAB ( because DC ║ AB )

And, ∠ PAB ≅ ∠ PBA

∠DPC ≅ ∠ APB ( reflexive)

Therefore, By AAA similarity postulate,

\triangle PDC \sim \triangle PAB

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⇒ PD = 33/7

Again by the definition of similarity,

\frac{PC}{PB} = \frac{DC}{AB}

\frac{PC}{PC+7} = \frac{11}{18} ( because PB = PC + CB)

⇒ 18 PC = 11 PD +77

⇒7PC = 77

⇒ PC = 11

Thus, PA =  PD+DA = 33/7 + 3 = 7\frac{5}{7}

And, PB = PC + CB = 11 + 7 = 18


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3 years ago
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Good afternoon. 

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 x   square ---   1h
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