Question

Given the following equilibrium constants:

Answer 1

Answer:

K = 8x10¹⁸

Explanation:

When you sum a reaction, the result of this sum has a K equal to the multiplication of the K's of the reactions involved in the sum

The sum of two times the reaction:

NaO(g) ⇌ Na(l) + 1/2 O₂(g) K₂ = 2x10⁻⁵

2 NaO(g) ⇌ 2 Na(l) + O₂(g) K = K₂ₓK₂ = (2x10⁻⁵)² = 4x10⁻¹⁰

The result of the inverse reaction:

Na₂O₂(s) ⇌ 2 Na(l) + O₂(g) K₃= 5x10⁻²⁹

2 Na(l) + O₂(g) ⇌ Na₂O₂(s) K = 1/K₃ = 2x10²⁸

And the sum of the two bolded reactions:

2 NaO(g) + 2 Na(l) + O₂(g) ⇌ 2 Na(l) + O₂(g) + Na₂O₂(s)

2 NaO(g) ⇌ Na₂O₂(s) K = 4x10⁻¹⁰× 2x10²⁸

K = 8x10¹⁸