Solution:-
- a=Carbon(c)
- b=Nitrogen ion(N+)
- c=Oxygen ion(O-)
Now
#1
Let's look at the EC of carbon(Z=6)
Now.
3 electrons are shared(1 with H_3C and 2 with N+)
Hence
Electron left unshared=4-3=1
#2
Lets look at EC of Nitrogen(N),Z=7
- Valency is 3
- It has already shared 3 electrons
But
Its Cation i.e N+
- Hence 1 electron it donated .Now it has valency 4
Hence
Electron left unshared=4-3=1
#3
Lets look at EC of Oxygen(Z=8)
But it is anion hence 1electron required more which us bonded
Hence
Number of electrons left unshared=0
Answer:
Cu₂O.
Explanation:
copper = 7.298
copper oxide = 8.217
oxygen in copper oxide = .919 g
7.298 g of copper = 7.298 / 63.5 mole of copper
= .1149 mole of copper
.919 g of oxygen = .919 / 16 mole of oxygen
= .0574 mole of oxygen
ratio of mole of copper and oxygen
= .1149 / .0574 = 2
formula of copper oxide = Cu₂O.
Answer:
0.004012km
Explanation:
Problem:
Conversion of millimeters(mm) to Kilometers:
value given = 4012mm
Here, we are converting from a submultiple unit to a multiple unit.
Millimeter depicts 10⁻³m and kilometer stands for 10³m
Now, we must find how many exponents will take us from 10⁻³ to 10³
careful examination shows that if we multiply a power of 10⁶ to 10⁻³ it will give a 10³:
i.e 10⁻³ x 10⁶ = 10⁻³⁺⁶ = 10³
Therefore,
10⁶mm = 1km
4,012mm = 
= 0.004012km
Answer:
1. Carbon Monoxide
2.Water
3. sulfuric acid
4.sulfur dioxide
Explanation:
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