<u><em>The process of how we would obtain </em></u><u><em>ethanal</em></u><u><em> </em></u><u><em>free</em></u><u><em> from ethanol is described in the explanations below. </em></u>
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- In Chemistry, Ethanol undergoes oxidation in the presence of sodium dichromate plus sulphuric acid to yield ethanal and water.
The procedure for achieving this in the laboratory is as follows;
- Step 1; Measure a quantity of a solution of sodium dichromate acidified in a dilute sulphuric acid and pour into a test tube.
- Step 2; Add excess <em>ethanol</em>. This is because if we don't do so there will be plenty of oxidizing agent to carry out a second operation which changes the aldehyde to ethanoic acid. However, we need only the aldehyde.
- Step 3; When the aldehyde ethanal begins to form which will be evident by the change in the colour of solution from <em>orange to green</em>, then the mixture should be distilled from the test tube and tbethe aldehyde collevted so that it doesn't undergo additional oxidation into ethanoic acid.
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There are different types of indicators for different neutralization reactions. The best indicator for giving a colour change at the equivalence point of a neutralization reaction depending on the pH range of a particular indicator and the equivalence point of the reaction. For instance, the best indicator for a neutralization reaction that involve the titration of NaOH with an acid which result in 9.00 equivalence point is phenolphtalein. This is because the equivalence point which is 9.00 is within the pH range of the indicator, which is between 8.0 to 10.1.
Answer:
C
Explanation:
A- incorrect, not in alphabetical order
B- incorrect, symbol for salt in NA not SA
C- correct
D- incorrect, not based on discovery
The answer is D solubility
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