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Kazeer [188]
2 years ago
12

Find the root of 11+2square30

Mathematics
1 answer:
EleoNora [17]2 years ago
5 0

\\ \sf\longmapsto \sqrt{11+2^230}

\\ \sf\longmapsto \sqrt{11+4(30)}

\\ \sf\longmapsto \sqrt{11+120}

\\ \sf\longmapsto \sqrt{131}

\\ \sf\longmapsto 11.3

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To find the equation of this line in slope-intercept form (y = mx + b, where m is its slope and b is its y-intercept), we naturally need the slope and the y-intercept. We can see that the line intersects the y-axis at the point (0, 4) so our y-intercept is 4, and the line rises 4 along the y-axis for every 2 it runs along the x-axis, so its slope is 4/2 = 2. With this in mind, we can write the line's equation as

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You pick a card at random, put it back, and then pick another card at random. 2 3 4 5 What is the probability of picking a numbe
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Answer:

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Step-by-step explanation:

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soldi70 [24.7K]

Answer:

\displaystyle m\angle AED=32.5^\circ

Step-by-step explanation:

<u>Angles in a Circle</u>

An exterior angle of a circle is an angle whose vertex is outside a circle and the sides of the angle are secants or tangents of the circle.

Segments AE and DE are secants of the given circle. They form an exterior angle called AED.

The measure of an exterior angle is equal to half the difference of the measure of their intercepted arcs.

Intercepted arcs in the given circle are AD=113° and BC=48°. The exterior angle is:

\displaystyle m\angle AED=\frac{AD-BC}{2}

\displaystyle m\angle AED=\frac{113^\circ-48^\circ}{2}=\frac{65^\circ}{2}

\displaystyle m\angle AED=32.5^\circ

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