Question

If one side of a rectangle is three less than the other side and the perimeter is 46 inches, find the area of the rectangle.

Answer 1

$a-one\ side\ of\ rectangle\\a+3-other\ side\ of\ rectangle\\2a+2(a+3)=2a+2a+6=4a+6-the\ perimeter\\46\ in-the\ perimeter\\\\\text{The equation:}\\\\4a+6=46\qquad\text{subtract 6 from both sides}\\\\4a=40\qquad\text{divide both sides by 4}\\\\a=10\\\\a+3=10+3=13\\\\\text{Dimensions of the rectangle:}\ 10\ in\ \times\ 13\ in.\\\\\text{The area of the rectangle:}\\\\\boxed{A=10\cdot13=130\ in^2}$