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patriot [66]
3 years ago
12

At a carnival, food tickets cost $2 each and ride tickets cost $3 each. A total of $1,240 was collected at the carnival. The num

ber of food tickets sold was 10 less than twice the number of ride tickets sold.
The system of equations represents x, the number of food tickets sold, and y, the number of ride tickets sold.

2x + 3y = 1240

x = 2y – 10

How many of each type of ticket were sold?

180 food tickets and 293 ride tickets
180 food tickets and 350 ride tickets
293 food tickets and 180 ride tickets
350 food tickets and 180 ride tickets
Mathematics
1 answer:
maria [59]3 years ago
7 0

Answer:

180 food tickets and 350 ride tickets

Step-by-step explanation:

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PLEASE HELPPP THANKS Solve |b| <= 5.
svetlana [45]
|b|\leq5\\
b\leq 5\wedge b\geq-5\\
b\in\langle-5,5\rangle
5 0
4 years ago
. Shanice is making a garden. The area of the garden is 24 ft2. Use the following shape and information to find the base (6−4) a
crimeas [40]

Answer:

The base and height  of the garden are 4.60 ft and 5.60 ft.

Step-by-step explanation:

The area of the garden is, <em>A</em> = 24 ft².

The base height of the garden are:

base (<em>b</em>) = 6x - 4

height (<em>h</em>) = x + 3

Compute the value of <em>x</em> as follows:

A=\frac{1}{2}\times b \times h\\\\24=\frac{1}{2}\times (6x-4) \times (x+3)\\\\48=6x^{2}+18x-4x-12\\\\6x^{2}+14x-60=0\\\\3x^{2}+7x-30=0\\

The last equation is a quadratic equation.

Compute the roots of the quadratic equation as follows:

x = \frac{ -b \pm \sqrt{b^2 - 4ac}}{ 2a }\\x = \frac{ -14 \pm \sqrt{14^2 - 4(3)(-30)}}{ 2(3) }\\x = \frac{ -14 \pm \sqrt{556}}{ 6 }\\x = \frac{ -14 }{ 6 } \pm \frac{2\sqrt{139}\, }{ 6 }\\x = -\frac{ 7}{  3 } \pm \frac{ \sqrt{139}\, }{  3 }\\x = 1.59661\\x\approx 1.60

The value of base and height are:

\text{base}=6x-4=(6\times 1.60)-4=5.60\ \text{ft}\\\\\text{height}=x+3=1.60+3=4.60\ \text{ft}

Thus, the base and height  of the garden are 4.60 ft and 5.60 ft.

3 0
3 years ago
If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a
harkovskaia [24]

Given:

The function is:

h(x)=x^2-3x+5

To find:

The value of h(2x+1).

Solution:

We have,

h(x)=x^2-3x+5

Putting x=2x+1, we get

h(2x+1)=(2x+1)^2-3(2x+1)+5

h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5

h(2x+1)=4x^2+4x+1-6x-3+5

On combining like terms, we get

h(2x+1)=4x^2+(4x-6x)+(1-3+5)

h(2x+1)=4x^2-2x+3

Therefore, the required function is h(2x+1)=4x^2-2x+3.

3 0
3 years ago
Does anyone know what 1/2*1/2*1/2*1/2 equals? <br> answers:<br> 4/48<br> 5/16<br> 1/20736<br> 4/12
dedylja [7]
I believe it would be 1/16.
3 0
3 years ago
Read 2 more answers
The perimeter of a rectangular field is 264 yards. If the width of the field is 54 yards, what is its length?
SIZIF [17.4K]
P = 2(L + W)
P = 264
W = 54

264 = 2(L + 54)
264 = 2L + 108
264 - 108 = 2L
156 = 2L
156/2 = L
78 <=== Length is 78 yards
7 0
3 years ago
Read 2 more answers
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