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patriot [66]
3 years ago
12

At a carnival, food tickets cost $2 each and ride tickets cost $3 each. A total of $1,240 was collected at the carnival. The num

ber of food tickets sold was 10 less than twice the number of ride tickets sold.
The system of equations represents x, the number of food tickets sold, and y, the number of ride tickets sold.

2x + 3y = 1240

x = 2y – 10

How many of each type of ticket were sold?

180 food tickets and 293 ride tickets
180 food tickets and 350 ride tickets
293 food tickets and 180 ride tickets
350 food tickets and 180 ride tickets
Mathematics
1 answer:
maria [59]3 years ago
7 0

Answer:

180 food tickets and 350 ride tickets

Step-by-step explanation:

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blagie [28]

Answer:

x = 38, y = 4

Step-by-step explanation:

Since AB = BC  then the triangle is isosceles and the base angles are congruent, that is

∠ DAB = ∠ DCB = 52°

Subtract the sum of the base angle from 180° for ∠ ABC

∠ ABC = 180° - (52 + 52)° = 180° - 104° = 76°

Note that ∠ ABD = ∠ CBD, thus

x = 76 ÷ 2 = 38

BD bisects the side AC, thus DC = AD = 4

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Kitty [74]

Answer:

The required answer is c=7\sqrt{3}

Therefore the number in green box should be 7.

Step-by-step explanation:

Given:

AB = 7√2

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∠B = 45°, ∠C = 30°

To Find:

c = ?

Solution:

In Right Angle Triangle ABD Sine identity we have

\sin B = \dfrac{\textrm{side opposite to angle B}}{Hypotenuse}\\

Substituting the values we get

\sin 45 = \dfrac{AD}{AB}= \dfrac{a}{7\sqrt{2}}

\dfrac{1}{\sqrt{2}}= \dfrac{a}{7\sqrt{2}}\\\\\therefore a=7

Now in Triangle ADC Tangent identity we have

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Substituting the values we get

\tan 30 = \dfrac{AD}{DC}= \dfrac{a}{c}\\\\\dfrac{1}{\sqrt{3}}=\dfrac{7}{c}\\\\\therefore c=7\sqrt{3}

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Answer:

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Step-by-step explanation:

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