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patriot [66]
3 years ago
12

At a carnival, food tickets cost $2 each and ride tickets cost $3 each. A total of $1,240 was collected at the carnival. The num

ber of food tickets sold was 10 less than twice the number of ride tickets sold.
The system of equations represents x, the number of food tickets sold, and y, the number of ride tickets sold.

2x + 3y = 1240

x = 2y – 10

How many of each type of ticket were sold?

180 food tickets and 293 ride tickets
180 food tickets and 350 ride tickets
293 food tickets and 180 ride tickets
350 food tickets and 180 ride tickets
Mathematics
1 answer:
maria [59]3 years ago
7 0

Answer:

180 food tickets and 350 ride tickets

Step-by-step explanation:

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slava [35]

Answer:

20,000/334 = 59.88, so each container can hold 60 pounds of sugar

Step-by-step explanation:

6 0
3 years ago
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What is the equation of the perpendicular bisector of line AB?
Usimov [2.4K]
It should be B

Because the slope of AB is 6/5 and when you are finding it’s perpendicular bisector then the slope of that line should be the negative reciprocal, it should be -5/6.
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3 years ago
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Find the scale factor of the smaller figure to the larger figure
guapka [62]

Answer:

#9: 1.2

#10: 1.25

Step-by-step explanation:

To find the scale factor of the smaller figure to the larger figure, we're going to be dividing the measurements of corresponding edges.

\frac{larger figure}{smaller figure}

If you wanted to find the scale factor of the larger figure to the smaller figure, you'd do: \frac{smaller figure}{larger figure}

Question #9:

Left edges: \frac{larger figure}{smaller figure} ⇒ \frac{24}{20} = 1.2

Bottom edges: \frac{larger figure}{smaller figure} ⇒ \frac{30}{25} = 1.2

<em>(You should get the same number as long as the figures are similar.)</em>

<em />

Question #10:

Bottom edges: \frac{larger figure}{smaller figure} ⇒ \frac{30}{24} = 1.25

<em>(There are no corresponding edges with measurements that we can compare.)</em>

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~Hope this helps!~

4 0
3 years ago
I don't need an explanation, I would just like the answer to these questions​
avanturin [10]

1)HGI ,S.S.S

2)DEF,A.S.A

3)C.E.D,S.A.S

6 0
3 years ago
1.
mr_godi [17]
Plug the points into the equation.
Ex. y=3x-5
(X,y)
1. (5,10): 10=3(5)-5
15-5=10; point 1 is valid
-1=3(-2)-5
-1=-6-5
-1 does not equal -11
Point 2 is not valid
Same process for letter B
8 0
3 years ago
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