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3 years ago

HELP ME PLS I WILL GIVE YOU THE BRAINEST

Mathematics

2 answers:

Fiesta28 [93]3 years ago

7 0

Answer:

The first term should be positive

She did not distribute the -4 properly

She added $\frac{2}{7}$ to negative -4 instead of multiplying

Step-by-step explanation:

In order to tell where she is wrong we should solve the question our selves. we are going to get the following......

$-4(-3x + \frac{2}{7})= -4(-3x) + (-4)(\frac{2}{7} )= 12x - \frac{8}{7}$

So now we see that the three things she did wrong are.

The first term should be positive

She did not distribute the -4 properly

She added $\frac{2}{7}$ to negative -4 instead of multiplying

Hope this helps :)

son4ous [18]3 years ago

3 0

Answer:

1, 4

Step-by-step explanation:

1. the product of two negatives are positive and they didn't do that, so yes.

2. the second term should NOT be positive, so they are correct on that.

3. they distributed the -4 correctly but added wrong, so they are correct on that.

4. -4+2/7=3 5/7 2/6(-4)=-4/3. They added instead of multiplying, so they are wrong.

5. they did simplify completely. they just did it wrong.

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What is the most precise classification of the quadrilateral formed by connecting in order the midpoints of the figure below? Sh

AlekseyPX

Answer:

Rhombus

Step-by-step explanation:

The given trapezoid has vertices at M(-4,0), J(-2,4), K(2,4), and L(4,0).

Use the midpoint formula: $(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

To obtain the midpoint of MJ:

$A=(\frac{-4+-2}{2},\frac{0+4}{2})=(-3,2)$

Similarly, the midpoint of of JK is B=(0,4), the midpoint of KL is C=(3,2), and the midpoint of LM is D=(0,0).

Now use the slope formula;

$m=\frac{y_2-y_1}{x_2-x_1}$

To find the slope of AB = $\frac{4-2}{0--3}=\frac{2}{3}$

The slope of BC = $\frac{2-4}{3-0} =-\frac{2}{3}$

The slope of CD= $\frac{0-2}{0-3}=\frac{2}{3}$

The slope of AD= $\frac{0-2}{0--3}=-\frac{2}{3}$

We can see that the slope of the opposites sides are parallel, CD is parallel to AB and AD is parallel to BC.

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The parallelogram is a rhombus.

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