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ArbitrLikvidat [17]
2 years ago
7

In building a tent, Jada ties a rope from the top of a pole 3 meters high to a stake that is 4 meters away from the base of the

pole. Jada draws this diagram to help find the angle made between the rope and the ground. Which equation can Jada use to find the value of x?

Mathematics
1 answer:
Leokris [45]2 years ago
3 0

Answer:

The answer is most definitely B

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From a standard deck of 52 cards, what is the probability of picking a Heart at random from the deck? A) 1 13 B) 1 26 C) 1 4 D)
monitta

Answer:

C 1/4

Step-by-step explanation:

13/52 = 1/4

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4 years ago
A square has a perimeter of 12x+52 units. Which expression represents the side length of the square in units?
Tpy6a [65]

Answer:

C. 3x+13

Step-by-step explanation:

Because

12x+52=

4(3x+13)

The 4 is the sides of a square

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3 years ago
70 POINTS!!!!!!!!!! Given: E, F, Q, D∈k(O),O ∈ ED, m∠DFQ = 10°, measure of arc EF = 28° Find: Angles of △EFQ
Likurg_2 [28]

Answer:

The measures of angles of triangle EFQ are

1) m\angle EFQ=100\°

2) m\angle FEQ=66\°

3) m\angle EQF=14\°

Step-by-step explanation:

step 1

Find the measure of arc QD

we know that

The inscribed angle is half that of the arc it comprises.

m\angle DFQ=\frac{1}{2}(arc\ QD)

substitute the given value

10\°=\frac{1}{2}(arc\ QD)

20\°=(arc\ QD)

arc\ QD=20\°

step 2

Find the measure of arc FQ

we know that

arc\ QD+arc\ FQ+arc\ EF=180\° ---> because ED is a diameter (the diameter divide the circle into two equal parts)

substitute the given values

20\°+arc\ FQ+28\°=180\°

arc\ FQ=180\°-48\°=132\°

step 3

Find the measure of angle EFQ

we know that

The inscribed angle is half that of the arc it comprises.

m\angle EFQ=\frac{1}{2}(arc\ QD+arc\ ED)

substitute the given value

m\angle EFQ=\frac{1}{2}(20\°+180\°)=100\°

step 4

Find the measure of angle FEQ

we know that

The inscribed angle is half that of the arc it comprises.

m\angle FEQ=\frac{1}{2}(arc\ FQ)

substitute the given value

m\angle FEQ=\frac{1}{2}(132\°)=66\°

step 5

Find the measure of angle EQF

we know that

The inscribed angle is half that of the arc it comprises.

m\angle EQF=\frac{1}{2}(arc\ EF)

substitute the given value

m\angle EQF=\frac{1}{2}(28\°)=14\°

5 0
4 years ago
On January 1, 2006, you have $100 in a savings account that earns interest at a rate of 1% per month. On the last day of every m
WINSTONCH [101]

Answer:

The recursive rule for account balance at the beginning of the nth month will be given by b_{1} = 100 and b_{n + 1} = b_{n} + 76 where, n = 1, 2, 3, .....

Step-by-step explanation:

On January 1, 2006, I have $100 in a savings account that earns interest at a rate of 1% per month. On the last day of every month, I deposit $75 in the account, beginning in January.

So, at the end of the month of January, the added amount to the account is $75 and 1% of $100 i.e. 1$.

Then, total $(75 + 1) = $76 is being added at the end of each month.

So, the recursive rule for account balance at the beginning of the nth month will be given by b_{1} = 100 and b_{n + 1} = b_{n} + 76 where, n = 1, 2, 3, ..... (Answer)

3 0
3 years ago
A random sample of students at North High School were polled on whether they prefer a 15-minute break between classes in the mor
bekas [8.4K]

This is late but, it's A. 21%

5 0
4 years ago
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