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Serhud [2]
3 years ago
15

PLEASE HELP WITH THIS QUESTION​

Mathematics
2 answers:
Maksim231197 [3]3 years ago
8 0

Answer:

8/10 = 8 divided by 10 = 0.8

7/10 = 7 divided by 10 = 0.7

to convert improper

3 x 2 = 6

6 + 1 = 7

so the fraction is 7/2

3 1/2 = 7/2 = 7/2 = 3.5

5/2 = 2.5 = 2 1/2

Hope this helps

Step-by-step explanation:

Karolina [17]3 years ago
7 0

Answer:

a) 0.8( 8/10 gives 0.8)

b)0.7( if it was 7/100 it would have been

0.07)

c)3.5( by converting mixed fractions to improper fractions, that is, 3×2+1 and having the same denominator 2… we get 7/2… for the purpose of converting it to decimal, 7×5/2*5= 35/10… by moving one decimal place to the left, we get 3.5)

D) 2.5 ( the same way as c) 5*5/2*5: 25/10 or you can make it to be 5*50/2*50: 250/100 which still gives 2.5)

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$45 changes to $56 what is the percent increase?
Lubov Fominskaja [6]
Change                      r
----------          =      -------          you use this formula, then cross multiply.
original                     100

56-45 =change      original=45
4 0
3 years ago
the area of a rectangular wall of a barn is 260 square feet. it's length is 6 feel longer than twice it's width. find the length
scoundrel [369]
L=2w+6
260=lw

Substitute for l
260=w(2w+6)
260= 2w^2+6w
2w^2+6w-260=0
2(w^2+3w-130)
2(w+13)(w-10)
w=-13, w=10

Since width cannot be negative it must be 10
260=l(10)
26=l

Final answer: length-26 ft, width-10ft
6 0
3 years ago
How do I do this??????
LUCKY_DIMON [66]
Just add the same sides and angles
8 0
3 years ago
Please help!!! I'm really confused​
Marrrta [24]

Answer:

1. a

2.c

3.d

4.c

5.b

6.d

Step-by-step explanation:

3 0
3 years ago
For the accompanying data set, draw a scatter diagram of the data.x 2 6 6 7 9y 3 2 6 9 5B. by hand compute the correlation coeff
zhenek [66]

Answer:

Step-by-step explanation:

Hello!

a.

Given the data corresponding the variables:

x 2 6 6 7 9

y 3 2 6 9 5

The Scatterplot is attached.

b.

To compute the correlation coefficient you need several auxiliary calculations:

∑X= 30

∑X²= 206

∑Y= 25

∑Y²= 155

∑XY= 162

r= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{\sqrt{[sumX^2-\frac{(sumX)^2}{n} ][sumY^2-\frac{(sumY)^2}{n} ]} }

r= \frac{162-\frac{(30)*(25)}{5} }{\sqrt{[206-\frac{(30)^2}{5} ][155-\frac{(25)^2}{5} ]} }

r= 0.429 ≅ 0.43

c.

The critical value for r has n-2 degrees of freedom, let's say for example you have α:0.05

r_{n-2;\alpha  } = r_{3;0.05 } = 0.878

For a two-tailed test.

Because the correlation coefficient is <u>positive</u> and the absolute value of the correlation coefficient, _<u>0.43</u>___, is <u>not greater</u> than the critical value for this data set,_<u>0.878</u>__, <u>no </u>linear relationship exists between x and y.

I hope it helps!

4 0
3 years ago
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