Change r
---------- = ------- you use this formula, then cross multiply.
original 100
56-45 =change original=45
L=2w+6
260=lw
Substitute for l
260=w(2w+6)
260= 2w^2+6w
2w^2+6w-260=0
2(w^2+3w-130)
2(w+13)(w-10)
w=-13, w=10
Since width cannot be negative it must be 10
260=l(10)
26=l
Final answer: length-26 ft, width-10ft
Just add the same sides and angles
Answer:
1. a
2.c
3.d
4.c
5.b
6.d
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello!
a.
Given the data corresponding the variables:
x 2 6 6 7 9
y 3 2 6 9 5
The Scatterplot is attached.
b.
To compute the correlation coefficient you need several auxiliary calculations:
∑X= 30
∑X²= 206
∑Y= 25
∑Y²= 155
∑XY= 162
![r= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{\sqrt{[sumX^2-\frac{(sumX)^2}{n} ][sumY^2-\frac{(sumY)^2}{n} ]} }](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7BsumXY-%5Cfrac%7B%28sumX%29%28sumY%29%7D%7Bn%7D%20%7D%7B%5Csqrt%7B%5BsumX%5E2-%5Cfrac%7B%28sumX%29%5E2%7D%7Bn%7D%20%5D%5BsumY%5E2-%5Cfrac%7B%28sumY%29%5E2%7D%7Bn%7D%20%5D%7D%20%7D)
![r= \frac{162-\frac{(30)*(25)}{5} }{\sqrt{[206-\frac{(30)^2}{5} ][155-\frac{(25)^2}{5} ]} }](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7B162-%5Cfrac%7B%2830%29%2A%2825%29%7D%7B5%7D%20%7D%7B%5Csqrt%7B%5B206-%5Cfrac%7B%2830%29%5E2%7D%7B5%7D%20%5D%5B155-%5Cfrac%7B%2825%29%5E2%7D%7B5%7D%20%5D%7D%20%7D)
r= 0.429 ≅ 0.43
c.
The critical value for r has n-2 degrees of freedom, let's say for example you have α:0.05

For a two-tailed test.
Because the correlation coefficient is <u>positive</u> and the absolute value of the correlation coefficient, _<u>0.43</u>___, is <u>not greater</u> than the critical value for this data set,_<u>0.878</u>__, <u>no </u>linear relationship exists between x and y.
I hope it helps!