1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nady [450]
3 years ago
10

from an observer o, the angles of elevation of the bottom and the top of a flagpole are 40° and 45° respectively.find the height

of the flagpole?​
Mathematics
1 answer:
maksim [4K]3 years ago
6 0

Answer:

Take a look of the image below, we can think on this problem as a problem of two triangle rectangles.

We can see that both triangles share the adjacent cathetus, then the height of the flagpole is just the difference between the opposite cathetus.

Remember the relation:

Tan(a) = (opposite cathetus)/(adjacent cathetus)

So, if we define H as the height of the cliff

X as the distance between the observer and the cliff

and h as the height of the flagopole

we can write:

tan(40°) = H/X

tan(45°) = (H + h)/X

Notice that we have two equations and 3 variables (we should have the same number of equations than variables) then here is missing information, and we can't get an exact solution for the height of the flagpole.

But we can write it in terms of the height of the cliff H, or in terms of the distance between the observer and the cliff.

We want to find the value of h.

If we take the quotient between both equations, we get:

Tan(45°)/Tan(40°) = (H + h)/H

1.192 = (H + h)/H

1.192*H = H + h

1.192*H - H = h

0.192*H = h

So the height of the flagpole is 0.192 times the height of the cliff.

You might be interested in
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
Order from Least to Greatest:<br><br> 1/4 <br> -0.8<br> 0.5 <br> -1.2
Shkiper50 [21]

Answer:

-1.2,-0.8,1/4,0.5

Step-by-step explanation:

hope this helps :D

3 0
3 years ago
Evaluate 10b + 3c, if b=3 and c = 11.
kozerog [31]

Answer:

63

Step-by-step explanation:

10 × 3 = 30

3× 11 = 33

30 + 33 = 63

4 0
2 years ago
How to show work for 36÷6
UkoKoshka [18]
36÷6 is 6 to show your work for it maybe draw it out and better show the equation like when you solve a bigger problem. 
6 0
3 years ago
Read 2 more answers
A square with side x is changing with time where x(t)=3t+1. What is rate of change of the area of the square when t=2 seconds.
GuDViN [60]

Answer:

Rate of change of the area of the square is 42 units at t = 2.

Step-by-step explanation:

We note that the area of the square is given by: A(x) = x^2 but we aim to find \frac{dA}{dt}. But we can use the chain rule to pull out that dA/dt. Doing so gives us:

\frac{dA}{dt} = \frac{dA}{dx} \times \frac{dx}{dt}.

Now, \frac{dA}{dx} = 2x (by the power rule and \frac{dx}{dt} = 3.

But since we have "x" and not "t", we want to find what x is when t = 2. Substituting t = 2 gives us x(2) = 3(2) + 1 = 7.

So, finally, we see that:

\frac{dA}{dt} = 2(7) \times 3 = 14 \times 3 = 42.

7 0
3 years ago
Other questions:
  • I made a square frame for my favorite bird picture from four wooden pieces. Each piece is a rectangle with a perimeter of 24 inc
    14·1 answer
  • HELP ASAP FIND AREA PLZ
    12·1 answer
  • Can u pls help me with this question ​
    13·1 answer
  • Please help im so confused​
    5·1 answer
  • The sum of two numbers is 191. One number is 17 less than the other number.
    10·1 answer
  • The quotient of a number and 2 is the same as the difference of the number doubled and 3. What is the number?
    8·1 answer
  • HELP PLS use the original price and markup to find the retail price. original price $68 markup 20%
    10·1 answer
  • 7th grade mathematics <br> help plz as soon as possible <br> Image is attached <br> 10 POINTS
    6·1 answer
  • Round 62.475 to the nearest hundredth.
    10·2 answers
  • Find the coordinates of the midpoint of each segment formed by the given points. (-4-4) &amp; (4-4).
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!