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galben [10]
3 years ago
14

What is 60 ten thousands

Mathematics
1 answer:
Levart [38]3 years ago
6 0
60 ten thousands. 60×10,000 is 600,000 so that is the answer.
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Brian is traveling at a rate of 72.0 meters/second. What speed would he be traveling in miles/hour?
Korvikt [17]

Answer:

we know that, 1miles/hour = 0.45m/s

or, 1meters/second = 1/0.45

1m/s = 2.22222222222

Step-by-step explanation:

Then,

72.0 meters/second = 72.0*2.22222222222

                                  =160 miles per hour.

7 0
3 years ago
Which equation can be used to represent the data in this table?
gtnhenbr [62]

ant Answer:

y=2x

Step-by-step explanation:

y=2x because you go up 2 and 1 to the right meaning, 2 x and 1 y

3 0
3 years ago
Name the angles below.
Ad libitum [116K]

Answer:

it's a obtuse angle...

8 0
3 years ago
Read 2 more answers
What is the answer? I don’t understand how to get it.
miss Akunina [59]

Answer:

A.

Step-by-step explanation:

Sub in the (x,y) points given into the equation to see if true ....you'll find A is the answer

Example  point (3,95 )      95 =  -10.375 (3) + 126.125    ??  

                                           95 = 95     Check !

               then try the other point ( 11,12) to be sure ....

             

5 0
2 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
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