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3 years ago

10

The train station clock runs too fast and gains 3 minutes every 2 days. How many minutes and seconds will it have gained at the

end of 3 days

1 answer:

swat323 years ago

5 0

Answer:

4.5 minutes will have been gained at the end of 3 days.

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The distance around the wheel of a truck is 9.42 feet .what's the diameter of the wheel

kap26 [50]

To solve this problem, you must follow the proccedure that is shown below:

1. You need to apply the formula for calculate the perimeter of a circle, which is:

P=2πr

P is the perimeter of the circle (P=9.42 feet).
r is the radius of the circle.

2. Now, you must clear the radius "r" from P=2πr, as below:

P=2πr
r=P/2π

3. When you substitute the values, you obtain:

r=P/2π
r=9.42 feet/2π
r=1.49 feet

4. Now, you can calculate the diameter (D):

D=2r
D=2(1.49 feet)
D=2.98 feet
<span>
What's the diameter of the wheel?

The answer is: </span><span>2.98 feet</span>

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4 years ago

Need to use a the table given to find the rate of change in fruit flies per day over the given intervals. Not sure how to use th

Aleksandr [31]

Given a table, with an input (x) and output (y) , you could actually use the slope formula to get the rate of change because slope is the same thing as rate of change. If you recall, the slope formula is (y2-y1)÷(x2-x1)
Just pick two points from the chart and plug them in and that is your rate of change

7 0

3 years ago

In a math problem what is 12+6=3+5

givi [52]

Answer:its incorrect... 18 does not equal 8

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

Simplify the difference.

mr_godi [17]

$\displaystyle\frac{n^2-10n+24}{n^2-13n+42}-\frac{9}{n-7}=\frac{(n-6)(n-4)}{(n-6)(n-7)}-\frac{9}{n-7}\\\\=\frac{n-4}{n-7}-\frac{9}{n-7}=\frac{n-4-9}{n-7}\\\\=\frac{n-13}{n-7}$

The last choice is appropriate.

3 0

3 years ago

uppose that Mary's utility function is U(W) = W0.5, where W is wealth. She has an initial wealth of $100. How much of a risk

Stels [109]

Note that $U(W) = W^{0.5}$

Answer:

Mary's risk premium is $0.9375

Step-by-step explanation:

Mary's utility function, $U(W) = W^{0.5}$

Mary's initial wealth = $100

The gamble has a 50% probability of raising her wealth to $115 and a 50% probability of lowering it to $77

Expected wealth of Mary, $E_w$

$E_{w}$ = (0.5 * $115) + (0.5 * $77)

$E_{w}$ = 57.5 + 38.5

$E_{w}$ = $96

The expected value of Mary's wealth is $96

Calculate the expected utility (EU) of Mary:-

$E_u = [0.5 * U(115)] + [0.5 * U(77)]\\E_u = [0.5 * 115^{0.5}] + [0.5 * 77^{0.5}]\\E_u = 5.36 + 4.39\\E_u = \$ 9.75$

The expected utility of Mary is $9.75

Mary will be willing to pay an amount P as risk premium to avoid taking the risk, where

U(EW - P) is equal to Mary's expected utility from the risky gamble.

U(EW - P) = EU

U(94 - P) = 9.63

Square root (94 - P) = 9.63

If Mary's risk premium is P, the expected utility will be given by the formula:

$E_{u} = U(E_{w} - P)\\E_{u} = U(96 - P)\\E_u = (96 - P)^{0.5}\\(E_u)^2 = 96 - P\\ 9.75^2 = 96 - P\\95.0625 = 96 - P\\P = 96 - 95.0625\\P = 0.9375$

Mary's risk premium is $0.9375

7 0

3 years ago