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ale4655 [162]
4 years ago
13

Ms. Lawton is redecorating her office. She has a choice of 4 colors of paint, 2 kinds of curtains, and 5 colors of carpet. How m

any different ways are there to redecorate?
Mathematics
1 answer:
Travka [436]4 years ago
5 0

Answer:

40 combinations

Step-by-step explanation:

We just multiply the outcomes.

4*2*5=40

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3.72 divided by 10 to the fourth power which of these shows and explains the correct location of the decimal point when the expr
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3 years ago
a rectangle is constructed with its base on the x-axis and two of its vertices on the parabola y=121-x^2. what are the dimension
insens350 [35]

Answer:

the length is \dfrac{22}{\sqrt{3}} and the width is 121-\left(\dfrac{11}{\sqrt{3}}\right)^2=121-\dfrac{121}{3}=\dfrac{242}{3}.

Step-by-step explanation:

Let points A and B be placed on the x-axis. Their coordinates are A(x_0,0)\ (x_0>0) and B(-x_0,0) (because of parabola symmetry). Two other vertices lie on the parabola, then C(-x_0,121-x_0^2) and D(x_0,121-x_0^2). The length of the side AB is 2x_0 and the length of the side AD is 121-x_0^2. Thus, the area of the rectangle ABCD is

A=2x_0\cdot (121-x_0^2)=242x_0-2x_0^3.

Find the derivative A':

A'=242-2\cdot 3x_0^2=242-6x_0^2.

Equate A' to 0:

242-6x_0^2=0,\\ \\x_0^2=\dfrac{121}{3},\\ \\x_0=\dfrac{11}{\sqrt{3}}.

The maximum area of the rectangle is

A_{max}=242\cdot \dfrac{11}{\sqrt{3}}-2\cdot \left(\dfrac{11}{\sqrt{3}}\right)^3=\dfrac{2662}{\sqrt{3}}-\dfrac{2662}{3\sqrt{3}}=\dfrac{5324}{3\sqrt{3}}\ un^2.

The dimensions of the rectangle are:

the length is \dfrac{22}{\sqrt{3}}\ un. and the width is 121-\left(\dfrac{11}{\sqrt{3}}\right)^2=121-\dfrac{121}{3}=\dfrac{242}{3}\ un.

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4 years ago
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Problem:<br>2x+3 (x-4)=x-20
monitta
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6 0
3 years ago
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