The probability that a student is a female or major in civil engineering is 62%
<h3>How to determine the probability?</h3>
Let A represent Female and B represents civil engineering.
So, we have:
P(A) = 49%
P(B) = 21%
P(A and B) = 8%
The required probability is calculated as:
P(A or B) = P(A) + P(B) - P(A and B)
This gives
P(A or B) = 49% + 21% - 8%
Evaluate
P(A or B) = 62%
Hence, the probability that a student is a female or major in civil engineering is 62%
<h3>Complete question</h3>
At a certain college, 49% of the students are female, and 21% of the students major in civil engineering. Furthermore, 8% of the students both are female and major in civil engineering. What is the probability that a randomly selected female student majors in civil engineering?
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Answer:
x = 11
Step-by-step explanation:
x + 5 = 2(x - 3)
x + 5 = 2x - 6
(x - x) + 5 = (2x - x) - 6
5 = x - 6
5 + 6 = x (- 6 + 6)
x = 11
Answer:
5/22
Step-by-step explanation:
A bag has 6 blue marbles, 4 red marbles, and 2 green marbles. Wo marbles are randomly chosen without replacement.
Total number of marbles =
6 blue marbles + 4 red marbles + 2 green marbles
= 12 marbles
The probability of picking a blue marble = P(B) = 6/12
Therefore, the probablilty that both marbles picked are blue without replacement is
= 6/12 × 5/11
= 30/132
= 5/22