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tigry1 [53]
3 years ago
8

Is 4/3 and 8/6 a proportion

Mathematics
2 answers:
FrozenT [24]3 years ago
7 0

Answer:

yes they are

when you multiply 4 x 2 you get 8 and when you divide 3 x 2 you get 6

Alexus [3.1K]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

If you divide one into the other and the answer is 1 then they are of the same ratio.

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What is 13 - x = -7 what is x in this equation
Zielflug [23.3K]

Answer:

x = 20

(hope i helped)

3 0
3 years ago
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Tony walks 1/3 of a mile to school each day. He also walks home from school. How many miles will he have walked in one five-day
djyliett [7]

Answer:

<h2> 3 1/3 miles per five day week</h2>
3 0
2 years ago
Determine the equation of the line that passes through (2,4) with a slope of -2/3
DedPeter [7]

Answer:

y = -2/3x + 16/3

Step-by-step explanation:

y = -2/3x + b

4 = -2/3(2) + b

4 = -4/3 + b

16/3 = b

4 0
3 years ago
1
Leona [35]

Given:

The inequality is:

y>5x+3

To find:

The y-intercept, slope and type of line (solid or dotted).

Solution:

The slope intercept form of a line is:

y=mx+b            ...(i)

Where, m is the slope and b is the y-intercept.

We have,

y>5x+3

The relation equation is:

y=5x+3             ...(ii)

On comparing (i) and (ii), we get

m=5

b=3

It means the slope is 5 and the y-intercept is 3.

The sign of the inequality in the given inequality is ">". It means the boundary line is not included in the solution set. So, the boundary line is a dotted line.

Therefore, the slope is 5, the y-intercept is 3 and the line is a dotted line.

7 0
3 years ago
When an electric current passes through two resistors with resistance r1 and r2, connected in parallel, the combined resistance,
kondaur [170]

Answer:

a)

The combined resistance of a circuit consisting of two resistors in parallel is given by:

\frac{1}{R}=\frac{1}{r_1}+\frac{1}{r_2}

where

R is the combined resistance

r_1, r_2 are the two resistors

We can re-write the expression as follows:

\frac{1}{R}=\frac{r_1+r_2}{r_1r_2}

Or

R=\frac{r_1 r_2}{r_1+r_2}

In order to see if the function is increasing in r1, we calculate the derivative with respect to r1: if the derivative if > 0, then the function is increasing.

The derivative of R with respect to r1 is:

\frac{dR}{dr_1}=\frac{r_2(r_1+r_2)-1(r_1r_2)}{(r_1+r_2)^2}=\frac{r_2^2}{(r_1+r_2)^2}

We notice that the derivative is a fraction of two squared terms: therefore, both factors are positive, so the derivative is always positive, and this means that R is an increasing function of r1.

b)

To solve this part, we use again the expression for R written in part a:

R=\frac{r_1 r_2}{r_1+r_2}

We start by noticing that there is a limit on the allowed values for r1: in fact, r1 must be strictly positive,

r_1>0

So the interval of allowed values for r1 is

0

From part a), we also said that the function is increasing versus r1 over the whole domain. This means that if we consider a certain interval

a ≤ r1 ≤ b

The maximum of the function (R) will occur at the maximum value of r1 in this interval: so, at

r_1=b

6 0
3 years ago
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