Answer:
The 99th tower contains 9900 blocks.
Step-by-step explanation:
From the question given, we were told that the nth tower is formed by stacking n blocks on top of an n times n square of blocks. This implies that the number of blocks in n tower will be:
n + n²
Now let us use the diagram to validate the idea.
Tower 1:
n = 1
Number of blocks = 1 + 1² = 2
Tower 2:
Number of blocks = 2 + 2² = 6
Tower 3:
Number of blocks = 3 + 3² = 12
Using same idea, we can obtain the number of blocks in the 99th tower as follow:
Tower 99:
n = 99
Number of blocks = 99 + 99² = 9900
Therefore, the 99th tower contains 9900 blocks.
Answer:
EG = 2 units
Step-by-step explanation:
Given that line q bisects EG at T , then
ET = TG ( substitute values )
x = x - 2 ( multiply through by 3 to clear the fraction )
x = 3x - 6 ( subtract x from both sides )
0 = 2x - 6 ( add 6 to both sides )
6 = 2x ( divide both sides by 2 )
3 = x
Then
ET =
x =
× 3 = 1
TG = x - 2 = 3 - 2 = 1
Thus
EG = ET + TG = 1 + 1 = 2 units
Answer: 45
Step-by-step explanation: the fub
Answer:
$147,848.5
Step-by-step explanation:
Fixed rate =7.35%
Mortgage Loan= $685,000
Selling price=$782,000
Property tax paid= $14,578.15
Therefore,
Prorated Amount Owed= Outstanding balance on the house + Interest paid on the loan for the year
Prorated Amount Owed=(782500-685000)+7.35% of 685000
=97500+50347.5
=$147,847.5
A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.
Answer: The correct option is B) about 34%
Proof:
We have to find 
To find
, we need to use z score formula:
When x = 4.2, we have:


When x = 5.1, we have:


Therefore, we have to find 
Using the standard normal table, we have:
= 

or 34.13%
= 34% approximately
Therefore, the percent of data between 4.2 and 5.1 is about 34%