Just saying this but don't go to that store! The answer, by the way is $1494
Therefore, f(x) = 2x + 3 is your derivative function, and you need to find the original curve. So find the antiderivative using the given conditions...
∫f(x) = ∫2x + 3 dx
F(x) = x^2 + 3x + C
2 = (1)^2 + 3(1) + C
2 = 4 + C
C= -2
Therefore, the curve is F(x) = x^2 + 3x - 2
Proof: The derivative is the slope at every (x, y) point. The derivative of F(x) comes out to be 2x + 3, so we have found the curve. Plug in x = 1, and y = 2, so the conditions have been met.
<span>Hope I helped.</span>
6 can go into 70 11 times without having a remainder so the 11 goes on the outside as your whole number. Then you have 4 left over to get to 70 so 4 becomes your numerator. The 6 stays as your denominator. So you have
Answer:
you do realize you're showing your face
Step-by-step explanation:
