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Y_Kistochka [10]
3 years ago
7

Given: Line A B intersects Line D E at point C. Prove: AngleDCB Is-congruent-toAngleECA Line D E intersects line B A at point C.

A 2-column table with 6 rows. Column 1 is labeled statements with the entries line A B intersects line D E at point C, angle D C B and angle B C E are a linear pair, angle D C B is supplementary to angle B C E, angle B C E and angle E C A are a linear pair, angle B C E is supplementary to angle E C A, angle D C B is-congruent-to angle E C A. Column 2 is labeled reasons with the entries given, definition of linear pair, linear pair post, definition of linear pair, question mark, congruent to supplementary theorem. What is the missing reason in step 5? linear pair postulate given definition of complementary angles congruent complements theorem
Mathematics
1 answer:
velikii [3]3 years ago
5 0

Answer:

The missing reason in step 5 is;

The linear pair postulate

Step-by-step explanation:

The information given are;

Column 1,                                                 Column 2

Statements,                                             Reasons

Line AB intersect DE at C,                      Given

∠DCB and ∠BCE are linear pair,           Definition of linear pair

∠DCB is supplementary to ∠BCE,         Linear pair postulate

∠BCE and ∠ECA are linear pair,           Definition of linear pair

∠BCE is supplementary to ∠ECA,         Linear pair postulate

∠DCB ≅ ∠ECA,                                      Congruent to supplementary theorem  

Therefore, the missing reason in step 5 is the linear pair postulate.

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Which is equivalent to the following expression <br> 7/12 times 4
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If a pair of regular dice are tossed once, use the expectation formula to determine the expected sum of the numbers on the upwar
Darya [45]

Answer:

The expected sum of the numbers on the upward faces of the two dice is 7.

Step-by-step explanation:

Consider the provided information.

If two pair of dice tossed the possible out comes are:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),  (5,6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5),  (6,6)

Now we need to find the expected sum of the numbers on the upward faces of the two dice.

The expected sums can be:

Sum:    2,      3,       4,       5,      6,      7,       8,        9,      10,    11,      12

Prob: 1/36, 2/36, 3/36, 4/36, 5/36, 6/36, 5/36, 4/36, 3/36, 2/36, 1/36

As we know that the expectation of experiment can be calculated as:

P(S_1)\cdot S_1+P(S_2)\cdot S_2+........+P(S_n)\cdot S_n

Here S represents the numerical outcomes and P(S) is the respective probability.

Substitute the respective values in the above formula.

=2\times\frac{1}{36}+3\times\frac{2}{36}+4\times\frac{3}{36}+5\times\frac{4}{36}+6\times\frac{5}{36}+7\times\frac{6}{36}+8\times\frac{5}{36}+9\times\frac{4}{36}+10\times\frac{3}{36}+11\times\frac{2}{36}+12\times\frac{1}{36}\\=\frac{252}{36}\\=7

Hence, the expected sum of the numbers on the upward faces of the two dice is 7.

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