2 years ago

Answer this question, thx for the help (the 4th one is this shape O )

1 answer:

5 0

Answer:

1st one

Step-by-step explanation:

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Monica [59]

The answer is -14 . i think

5 0

2 years ago

sergiy2304 [10]

Sophia is more correct in her solution.

7 0

3 years ago

AleksAgata [21]

Answer:

Step-by-step explanation:

Given

$6x_1-9x_2=8$

$9x_1+kx_2=-1$

The given system is $AX=B$ can be represented by

$\begin{bmatrix}6 &-9 \\ 9 & k\end{bmatrix}\begin{bmatrix}x_1\\ x_2\end{bmatrix}=\begin{bmatrix}8\\ -1\end{bmatrix}$

The given system is consistent when determinant of A is not equal to zero

$|A|$

$|A|=6k-(-81)=6k+81$

$k\neq \frac{-27}{2}$

i.e. system is consistent for all value of k except $k=\frac{-27}{2}$

$R-\frac{-27}{2}$

4 0

3 years ago

yaroslaw [1]

It’s ether 138.6 or 101.4. 123 rounded to the nearest tenth is 120 so you ether add or subtract

4 0

3 years ago

barxatty [35]

418-261=157
Answer: 157
I think this is what the problem is asking

7 0

2 years ago