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kifflom [539]
3 years ago
11

George wishes to increase the percent of acid in 50ml of a 15% acid solution to 25% acid, how much pure acid must he add?

Mathematics
2 answers:
sdas [7]3 years ago
6 0
I think u will need to add 5ml acid into the solution to get 25% acid

const2013 [10]3 years ago
3 0

Let's use the decimal equivalent of percent. He has 50 ml of a 0.15 acid solution. He wants the concentration of acid to increase to 0.25 by adding pure acid.

concentration = (volume of acid)/(total volume of solution)

He takes the current solution and add x amount of pure acid.

15% of 50 ml = 7.5 ml

The current 15% solution contains 7.5 ml of pure acid. The x amount of acid he adds is added onto the 7.5 ml of acid he already has and it is also added to the total volume of 50 ml.

(7.5 + x)/(50 + x) = 0.25

7.5 + x = 0.25(50 + x)

7.5 + x = 12.5 + 0.25x

0.75x = 5

x = 6.6666...

Answer: 6 2/3 ml

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Answer:

Option: B is the correct answer.      

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Step-by-step explanation:

We are given an exponential equation as follows:

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We know that any exponential function of the type:

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is growth function if: b>1

and is a decay function if 0< b< 1

Hence, here we have: b=0.66<1

Hence, the function is a decay function.

Also, we know that the y-intercept of a function is the point where x=0

Hence, we take x=0

we have:  y=3.4\times (0.66)^0\\\\\\y=3.4

Hence, the y-intercept is:   3.4

Also, the rate of a function is denoted by 'r'

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    ⇒ r=0.34

Hence, the rate is: 34%

          option: B is the correct answer.

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