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fgiga [73]
3 years ago
15

If there are 9 candies, and 4 of them are yellow, how many does that leave?

Mathematics
2 answers:
Jobisdone [24]3 years ago
8 0
There would be 5 more candies
pentagon [3]3 years ago
3 0
There are still 9 candies. The color of them is besides the point.
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Solve the equation by factoring. 8x^2+10x-7=0<br><br> What is the solution set?
nydimaria [60]

Answer:

\large \text{$x_1$}=-\dfrac{7}{4}, \large \text{$x_2$}=\dfrac{1}{2}

Step-by-step explanation:

Given: 8x² + 10x - 7 = 0

<u>When factoring trinomials of the form ax² + bx + c</u>:

  • multiply the leading coefficient and the last term.
  • find the product factors that add to give you the coefficient of the middle term.
  • rewrite the polynomial with those factors replacing the middle term.

1. Split the middle term:

⇒ 8 × -7 = -56 [multiply the leading coefficient and the last term]

⇒ 14, -4 [find the product factors that add to the middle term's coefficient]

⇒ 8x² + 14x - 4x - 7 = 0 [rewrite with those factors replacing the middle term.]

2. Factor by grouping:

⇒ 8x² + 14x - 4x - 7 = 0 [factor out 2x]

⇒ 2x(4x + 7) - 4x - 7 = 0 [factor out -1 or the negative sign]

⇒ 2x(4x + 7) -1(4x + 7) = 0 [factor out 4x + 7]

⟹ (4x + 7)(2x - 1) = 0

3. Separate into 2 cases:

  1. 4x + 7 = 0
  2. 2x - 1 = 0

 

<u><em>Case 1:</em></u>

⇒ 4x + 7 = 0 [subtract 7 from both sides]

⇒ 4x + 7 - 7 = 0 - 7

⇒ 4x = -7 [divide both sides by 4]

⇒ 4x ÷ 4 = -7 ÷ 4

⟹ x = \bold{-\dfrac{7}{4}}

<u><em>Case 2:</em></u>

⇒ 2x - 1 = 0 [subtract 1 from both sides]

⇒ 2x - 1 + 1 = 0 + 1

⇒ 2x = 1 [divide both sides by 2]

⇒ 2x ÷ 2 = 1 ÷ 2

⟹ x = \bold{\dfrac{1}{2}}

Solutions:

\large \text{$x_1$}=-\dfrac{7}{4}, \large \text{$x_2$}=\dfrac{1}{2}

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

brainly.com/question/27638369

7 0
2 years ago
Read 2 more answers
If PQR is an equilateral triangle, PQ=18x+1, QR=24x-17, and PR=15x+10, find x and the measure of each side.
Vadim26 [7]

Answer

QR= PQ= PR

18x+1= 24x-17

18x-24x= -17-1

-6x= -18

x= 3

QR= 24(3)-17= 55

PQ= 18(3)+1= 55

PR= 15(3)+10=55

8 0
3 years ago
Read 2 more answers
Can you help me with this
kifflom [539]

Answer:

the anwer is d

I did the math

8 0
2 years ago
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What is 16,473 to the nearest hundred
Verizon [17]
The number "4" is in the hundreds place. To the right is 7, and since it's greater than five it rounds up. So 16,473 to the nearest hundred is 16,500. Hope this helped!
4 0
3 years ago
3x^3-2x^2-147x+98=(ax-c)(bx+d)(bx-d) where a,b,c and d positive integers. Work out the value of a,b,c and d
Alexxx [7]

Expand the right side:

(ax-c)(bx+d)(bx-d)=(ax-c)(b^2x^2-d^2)

=ab^2x^3-b^2cx^2-ad^2x+cd^2

Notice that 98 = 2 * 7 * 7, so we have c=2 and d=7.

Then

-ad^2=-147\implies a=\dfrac{147}{49}=3

and

ab^2=3\implies b^2=1\implies b=1

6 0
3 years ago
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