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Yuri [45]
3 years ago
11

Find a5, when a1 =4, r=5

Mathematics
1 answer:
sasho [114]3 years ago
3 0

Answer:

Answer: a5 = 2500

Step-by-step explanation:

For a geometric sequence:  

First term = a0  

Second term = a1 = a0*r  

Third term = a2 = a0*r^2  

Fourth term = a3 = a0*r^3  

....  

nth term = a(n-1) = a0*r^(n-1)  

Given: a1 = 4 = a0*r  

Also: r = 5  

So, a0*5 = 4 => a0 = (4/5)  

a5 = a(6-1) = Sixth term = a0*r^5 = (4/5)*5^5 = 2500  


Hope this helps

correct me if im wrong☺


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