Find a5, when a1 =4, r=5

Mathematics

1 answer:

sasho [114]3 years ago

3 0

Answer:

Answer: a5 = 2500

Step-by-step explanation:

For a geometric sequence:

First term = a0

Second term = a1 = a0*r

Third term = a2 = a0*r^2

Fourth term = a3 = a0*r^3

....

nth term = a(n-1) = a0*r^(n-1)

Given: a1 = 4 = a0*r

Also: r = 5

So, a0*5 = 4 => a0 = (4/5)

a5 = a(6-1) = Sixth term = a0*r^5 = (4/5)*5^5 = 2500

Hope this helps

correct me if im wrong☺

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