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uranmaximum [27]
4 years ago
5

A multiple-choice examination has 20 questions, each with five possible answers, only one of which is correct. Suppose that one

of the students who takes the examination answers each of the questions with an independent random guess. What is the probability that he answers at least seventeen questions correctly? (Round your answer to three decimal places.)
Mathematics
1 answer:
kari74 [83]4 years ago
4 0

Answer:

The probability that the student answers at least seventeen questions correctly is 8.03\times 10^{-10}.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of correctly answered questions.

It is provided all the questions have five options with only one correct option.

Then the probability of selecting the correct option is,

P(X)=p=\frac{1}{5}=0.20

There are <em>n</em> = 20 question in the exam.

It is also provided that a student taking the examination answers each of the questions with an independent random guess.

Then the random variable can be modeled by the Binomial distribution with parameters <em>n</em> = 20 and <em>p</em> = 0.20.

The probability mass function of <em>X</em> is:

P(X=x)={20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x};\ x =0,1,2,3...

Compute the probability that the student answers at least seventeen questions correctly as follows:

P(X\geq 17)=P (X=17)+P (X=18)+P (X=19)+P (X=20)

=\sum\limits^{20}_{x=17}{{20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x}}\\\\=0.00000000077+0.000000000032+0.00000000000084+0.000000000000042\\\\=0.000000000802882\\\\=8.03\times10^{-10}

Thus, the probability that the student answers at least seventeen questions correctly is 8.03\times 10^{-10}.

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ankoles [38]

Using the given information, length of QR = 16.6 cm

The area of the trapezium is 304.5 cm²

<h3>Calculating area of a trapezium</h3>

From the question we are to calculate the length of QR and the area of trapezium PQRS

In the given diagram,

Let the midpoint of PS be T

Then, we can write that

|OP|² = |OT|² + |PT|²  (<em>Pythagorean theorem</em>)

|OP| = radius = 13 cm

|PT| = 1/2 × PS = 1/2 × 24 cm = 12 cm

∴ 13² = |OT|² + 12²

169 = |OT|² + 144

|OT|² = 169 -144

|OT|² = 25

|OT| = √25

|OT| = 5 cm

Also, let the midpoint of QR be U

Then, we can write that

|OQ|² = |OU|² + |QU|² (<em>Pythagorean theorem</em>)

|OQ| = radius = 13 cm

From the given information,

The distance of QR from O is twice the distance of PS from O

∴ |OU| = 2 × |OT|= 2 × 5 cm = 10cm

Thus,

13² = ||² + 12²

169 = 10² + |QU|²

|QU|² = 169 -100

|QU|² = 69

|QU| = √69

|QU| = 8.3 cm

Now,

Length of QR = 2 × |QU| = 2 × 8.3 cm

Length of QR = 16.6 cm

b)

Area of the trapezium = 1/2(|QR| + |PS|) × |TU|

Area of the trapezium = 1/2(16.6 + 24) × 15

NOTE: |TU| = |OT| + |OU|

Area of the trapezium = 1/2(40.6) × 15

Area of the trapezium = 20.3 × 15

Area of the trapezium = 304.5 cm²

Hence, the area of the trapezium is 304.5 cm²

Learn more on Calculating area of trapezium here: brainly.com/question/3435635

#SPJ1

7 0
2 years ago
A pack of 13 candles is priced at $78. At that rate, how much would only 10 candles cost?
Sphinxa [80]

Answer:

78/13 = 6 (is the price of one candle)

6(price) x 10(candles) =60 is the answer

Hope it helped

8 0
3 years ago
A man has 14 coins in his pocket, all of which are dimes and quarters. If the total value of his
S_A_V [24]

Answer:

9 quarters 5 dimes!

Step-by-step explanation:

9x0.25=2.25

5x0.10=0.50

2.25+0.50=2.75

6 0
3 years ago
The distance between City A and City B is 200 miles. A length of 2.1 feet represents this distance on a certain wall map. City C
ratelena [41]

Answer:

300 miles

Step-by-step explanation:

200/2.1= 95.238...

95.238...*3.15=300

Hope this helps :)

3 0
3 years ago
Read 2 more answers
Joanie is making a map of the trails in the community park . Two of the trails start at the same point and a forty degree angle.
Grace [21]

Answer:

Draw a line on you paper, go to the start of the line and place your Protractor. Look for the 40 degree mark and place a little slash there. Take away the protractor and draw a line going through the slash. (Use a ruler too)

Step-by-step explanation:

For this you need a protractor

6 0
3 years ago
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