Solving the given inequality for d, we get...
6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83
Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}
The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6
Answer:
One solution
Step-by-step explanation:
6x+35=-6x+35
Add 6x to both sides (addition property of equality)
12x+35=35
Subtract 35 from both sides (subtraction property of equality)
12x=0
Divide both sides by 12 (division property of equality)
x=0
Therefore there is only one solution, 0.
Answer:10
Step-by-step explanation:
