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Semenov [28]
3 years ago
14

Graph the inequality

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
4 0
This should be it man

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Find the center of the circle whose equation is (x - 8) 2 + (y + 2) 2 = 64.
SashulF [63]

If given the equation, you need to take the number beside the x and y and change their signs to get your point:

x - 8 (Take the -8 and make it +8)

y + 2 (Take the +2 and make it -2)

Your point is (8, -2)

4 0
3 years ago
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Sega makes brownies using a square pan that has a side
Black_prince [1.1K]

Answer:

(x+6)*(x+6)

Step-by-step explanation:

8 0
3 years ago
A line goes through the point (–4,–2) and has an x-intercept of –1. Which point also lies on the line? 
Yuki888 [10]
Im not getting exact answers but the closest was D. What i did was i graphed the points and i found the slope and then i found the y intercept. so the equation was y = 2/3x + .67. and i plugged in the points. so i would say the answer is D. because since i rounded the .67 it wasn't exact but it was close

4 0
3 years ago
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What is the equation of the line that passes through (-9,12) and is perpendicular to the line whose equation is y=1/3x 6?
tigry1 [53]
Y = 1/3x ? 6....slope here is 1/3. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So our perpendicular line will have a slope of -3 (see how I flipped 1/3 and changed the sign)

y = mx + b
slope(m) = -3
(-9,12)...x = -9 and y = 12
now we sub and find b, the y int
12 = -3(-9) + b
12 = 27 + b
12 - 27 = b
-15 = b

so ur perpendicular equation is : y = -3x - 15
6 0
3 years ago
How do you solve -x/6 > 3?
Lerok [7]

Answer:

Using Math.

Step-by-step explanation:

You solve it using math.

See, you should have been more specific with your question, maybe said "What is the answer" not "How do I solve".

But I guess I'll help you out bro

<em>Multiply</em> both sides by 6

that gives you -x>18

then <em>multiply</em> both sides by -1

which means you gotta <u>flip the sign</u>

so final answer is x<-18

4 0
3 years ago
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