Answer:
(1, 2 )
Step-by-step explanation:
Under a reflection in the x- axis
a point (x, y ) → (x, - y ), thus
C(1, - 2 ) → C'(1, 2 )
Answer:
Pick A
Step-by-step explanation:
Step by step, hope this helps
Success = p
failure = (1-p)
is the correct first step.
To find the probability of at least one success, P(X>0), it is much easier to first calculate the probability of P(X=0)=NO success. Then the complement of
P(X=0)'=1-P(X=0) = P(>0) = probability of at least one success.
By the multiplication rule,
P(X=0)=(1-p)^9
or the binomial distribution
P(X=0)=C(9,0)(p^0)(1-p)^9=1*1*(1-p)^9=(1-p)^9
So the probability of at least one success = 1-P(X=0)
=1-(1-p)^9
Answer:
96
Step-by-step explanation
4(x - 2)(x + 3) + 7(x - 2)(x - 5) - 6(x - 3)(x - 5)
4(5 - 2)(5 + 3) = 12(8) = 96
7(5 - 2)(5 - 5) = 0
- 6(5 - 3)(5 - 5)= 0
96+0-0 = 96
Answer:
First Game: 65 points
Second Game : 65 points
Third Game : 59 points
Step-by-step explanation:
Average = sum of values/number of values
The number of values = 3, an d average = 63
63 = x/3
63 * 3 = x
189 = x
Now 189 is the sum of points over two games.
Their first two games are worth the same, so lets call that s +s = 2s
Their 3rd game is worth 6 less points than s, so s-6
let's add up all the terms:
2s + (s - 6) = 3s - 6
Solve:
3s - 6 = 189
3s = 195
s = 65
The first two games are worth 65, and the third game is worth 65 - 6 = 59.
-Chetan K
