The probability of the offspring of a heterozygous father and homzygous mother having five fingers is 50%.
<h3>How to calculate genotype of a cross?</h3>
According to this question, a gene coding for the number of fingers in humans is involved. The allele for six fingers (F) is the dominant trait while the allele for five fingers (f) is the recessive trait.
If a cross between a heterozygous father that posseses a genotype of Ff and a homzygous mother that posseses a genotype of ff, the following offsprings will be produced:
This shows that the probability of the offspring of a heterozygous father and homzygous mother having five fingers is ½ (50%).
Learn more about genotype at: brainly.com/question/12116830
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Your own genetic code could be responsible for inviting diabetes into the cell cycle
Explanation:
sensory so hard but I will try
<span>The answer would be: Continue patient care by getting a complete SAMPLE history and perform a complete secondary assessment.
If the reading of glucose test is normal, then you can exclude hypoglycemia from the possible diagnosis. Because the patient is accompanied by his mother, you can ask a brief history to exclude other possible diagnosis and complete secondary assessment before further help comes. The information would be beneficial to the healthcare personnel that will comes for help.
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Answer:
The visible DNA fingerprint can help extract DNA which, after analysis, can accurately identify the suspect or perpetrator of the crime.
Explanation:
DNA Fingerprinting:
- DNA fingerprinting is a molecular analysis tool that can help identify a suspect in a crime through DNA extracted from fingerprints.
- Specific patterns in the DNA, known as polymorphisms, can be identified through DNA fingerprinting.
- The DNA fingerprinting process involves:
- Extraction and purification of the DNA from the fingerprint.
- PCR amplification to obtain high yield.
- Fragmentation of the DNA by use of restriction enzymes.
- Gel electrophoresis analysis of the fragmented DNA.
- Analysis of gel to compare the size of the bands.
