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marysya [2.9K]
3 years ago
7

A client has been admitted to the emergency department. the client's family tells the nurse that the client has suddenly become

lethargic and is "not making sense." the client has not had anything to eat or drink for the last 8 hours. the nurse further assesses the client using the confusion assessment method (cam). the client's responses to questions are rambling, and the client is not able to focus clearly to answer the nurse's questions. based on these findings, the nurse should report that the client has:
Biology
1 answer:
Phoenix [80]3 years ago
6 0
The correct answer is delirium.
The Confusion Assessment Method (CAM) is a psychiatric tool used to assess and identify delirium in patients. According to the first observations and the patient's responses to CAM, the nurse can conclude that the patient exhibits signs of delirium. This is because he is unable to concentrate and organize his thinking, he is inattentive, he is lethargic and all these behaviours are sudden and acute. These symptoms cannot be associated with dementia, as dementia develops gradually and doesn't affect attention and consciousness. Also, the symptoms don't point to depression since depressive patients are focused and attentive. Finally, the nurse cannot conclude that the patient is dehydrated because further tests need to be conducted to assess hydration. 
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3 years ago
You are a biologist examining local bird populations in your area. You have noted that there appears to be several varieties of
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In a population of rabbits, there are 496 black rabbits and 27 white rabbits. Fur color is determined by a pair of alleles where
Troyanec [42]

Answer:

0.96

Explanation:

It is given that

B is the dominant allele which represents the black color

and b is the recessive allele which represents the white fur.

B being dominant will result into black color fur for genotype "Bb"

Given -

Frequency of black fur allele (p) is 0.8

As per Hardy Weinberg's  first law of equilibrium

p + q = 1\\

Substituting the value of p in above equation, we get -

q = 1-p\\q = 1-0.8\\q= 0.2

q represents the frequency for white fur allele

Frequency of white fur phenotype is

q^2\\= 0.2^2\\= 0.04

Frequency of homozygous black fur phenotype (BB) is

p^2\\= 0.8^2\\= 0.64

As per Hardy Weinberg's second law of equilibrium -

p^2 + q^2 + 2pq = 1\\0.64 + 0.04 + 2pq = 1\\2pq = 1 - 0.68\\2pq = 0.32\\

Combined frequency of homozygous and heterozygous black fur phenotype is

0.64 + 0.32\\= 0.96

5 0
3 years ago
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