Slope: (y2-y1)/(x2-x1)
(-13-(-7)) = -6
-6/3 = -2
x - 3 = 3, x = 6
The solution: x = 6
<h3>
Answer: E) Not enough information</h3>
We're given two pairs of congruent sides, and a pair of congruent angles. The angles are not between the two congruent sides. So we don't have enough information to know if the triangles are congruent or not. SSA is not a valid congruence theorem. This is because there are some cases where two triangles are possible leading to ambiguity.
If the marked angles were between the tickmarked sides, then we could use SAS.
We have here as
as
, then the values are.
![\mu = 80](https://tex.z-dn.net/?f=%5Cmu%20%3D%2080)
s=8.7
For the resulting of the test by the teacher he had,
![\bar{X}=80,s=8.7](https://tex.z-dn.net/?f=%5Cbar%7BX%7D%3D80%2Cs%3D8.7)
With all of this dates to make the comparition we use the formula for Z values, that is
![z=\frac{\bar{x}-\mu}{\frac{\sigma}{ \sqrt{n}}}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B%5Cbar%7Bx%7D-%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%20%5Csqrt%7Bn%7D%7D%7D)
![z=\frac{80-85}{\frac{10.9}{43}}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B80-85%7D%7B%5Cfrac%7B10.9%7D%7B43%7D%7D)
![z=-3.008 = 3.01](https://tex.z-dn.net/?f=z%3D-3.008%20%3D%203.01)
We know moreover that
= 0.052.
To find
we need to find ![1-\alpha/2](https://tex.z-dn.net/?f=1-%5Calpha%2F2)
![1-\alpha/2=1-0.052/2 =0.974](https://tex.z-dn.net/?f=1-%5Calpha%2F2%3D1-0.052%2F2%20%3D0.974)
Searching in the table of Normal Distribution for Z, and making the lecture we find that z_{critic} is, 1.95.
You don't add or subtract the denominator. when you compare fractions like 1/4 and 1/8 you have to find the factors that repusent that like 2×4=8 so 4 2 is ur awnser
The answer is 3.
5, 4, 3, 2, 1
The number after 4 is 3.
Hope this helped☺☺