Ms. Cassidy instructed Miguel to change one sign of the graph of y < 2x – 4 so that point (2, 3) can be included in the solution set.
To check which of the given options might Miguel write we check the inequality that holds true for the point (2,3).Substituting x=2 ,y=3 we have:
1) y < 2x – 1
3<2(2)-1
3<3 Not True.
2)y ≤ 2x – 4
3≤ 2(2) -4
3≤ 0 .Not true.
3) y > 2x – 4
3> 2(2)-4
3> 0 True.
4) y < 2x + 4
3<2(2)+4
3<8 True
5) .y < 3.5x – 4
3< 3.5(2)-4
3<3 Not true
6) y < 4x – 4
3<4(2)-4
3<4 True.
Options 3 ,4 ,6 holds true for the point (2,3)
Answer:
Part 1) 
Part 2) 
Part 3) 
Part 4) 
Part 5) 
Part 6) 
Step-by-step explanation:
Part 1) we know that
The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle
The area of rectangle is equal to

where
b is the base of rectangle
h is the height of rectangle
so



Part 2) we know that
The shaded region is equal to the area of the complete rectangle minus the area of the interior square
The area of square is equal to

where
b is the length side of the square
so



Part 3) we know that
The area of the shaded region is equal to the area of four rectangles plus the area of one square
so



Part 4) we know that
The shaded region is equal to the area of the complete square minus the area of the interior square
so



Part 5) we know that
The area of the shaded region is equal to the area of triangle minus the area of rectangle
The area of triangle is equal to

where
b is the base of triangle
h is the height of triangle
so



Part 6) we know that
The area of the shaded region is equal to the area of the circle minus the area of rectangle
The area of the circle is equal to

where
r is the radius of the circle
so


4^7=16,384 i used a calulator
Answer:
11 and 5/16
Hope this answers your question
No because the sides are different if they were the same they would be a right triangle