You have two equations.
since the second is already isolated, sub in x-4 for every y in equation 1 so that
![x^{2} - 4 [(x-4)^{2}] =16 ](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20-%204%20%5B%28x-4%29%5E%7B2%7D%5D%20%3D16%0A%20)
expand, collect like terms, factor to find x, then plug x value back into original equation to find y
Answer:
Step-by-step explanation:
This is because you use Pythagorean theorem. a^2 + b^2 = c^2.
The correct answer is: " 
" .
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<u>Step-by-step explanation</u>:
Based on the assumption that the "1" repeats infinitely; in the given value:
" 33.61111111 ...." ;
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Note that the "611" ; after the decimal point; this goes to the "thousandths";
place (is "3 (three) digits long.").
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As such; we rewrite the number as:
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" 
" ;
and we multiply BOTH the "numerator" And the "denominator" by: "1000" :
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→ " 
" ;
to get:
→ " 
" ; → which cannot be reduced any further.
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The correct answer is: " " .
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Hope this is helpful to you!
Wishing you the best!
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Answer:
c
Step-by-step explanation:
come on ! you can literally see that in the chart.
how many parts of the gray 3/8 are covered by the gray 1/4 ?
2 parts = 2/8 are clearly covered by 1/4.
2/8 is what part of 3/8 ?
it is the same question as "2 is what part of 3" ?
is 2 a quarter (1/4) of 3 ? no, 1/4×3 = 3/4 and not 2.
is 2 one third (1/3) of 3 ? no, 1/3 of 3 = 1/3×3 = 1 and not 2.
is 2 two thirds (2/3) of 3 ? ah, 2/3 × 3 = 2. that is correct !
is 2 three quarters (3/4) of 3 ? no, 3/4×3 = 9/4 and not 2.
once you have the same denominator, you can easily compare the numerators and ignore the denominators for such problems.
Answer:
Step-by-step explanation:
We want to find the sum of
We can rewrite this as
This becomes;
Recall that;
This implies that;
Combine like terms:
