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Snezhnost [94]
3 years ago
13

Write a function PrintShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, pr

int "Too few.". If more than 4, print "Too many.". Else, print "N: Lather and rinse." numCycles times, where N is the cycle number, followed by "Done.". End with a newline. Example output for numCycles = 2:
1: Lather and rinse.
2: Lather and rinse.
Done.
Hint: Define and use a loop variable.
Sample program:
#include
using namespace std;

int main() {
PrintShampooInstructions(2);
return 0;
}
Computers and Technology
2 answers:
Finger [1]3 years ago
8 0

Answer:

public static void PrintShampooInstructions(int numberOfCycles){

       if (numberOfCycles<1){

           System.out.println("Too Few");

       }

       else if(numberOfCycles>4){

           System.out.println("Too many");

       }

       else

           for(int i = 1; i<=numberOfCycles; i++){

               System.out.println(i +": Lather and rinse");

           }

       System.out.println("Done");

   }

Explanation:

I have used Java Programming language to solve this

Use if...elseif and else statement to determine and print "Too Few" or "Too Many".

If within range use a for loop to print the number of times

Nady [450]3 years ago
4 0

Answer:

#In Python

def shampoo_instructions(num_cycles):

   if num_cycles < 1: ///

       print ('Too few.') ///

   elif num_cycles > 4:

       print ('Too many.')

   else:

       i = 0

       while i<num_cycles:

           print (i+1,": Lather and rinse.")

           i = i + 1

       print('Done.')

user_cycles = int(input())

shampoo_instructions(user_cycles)

Explanation:

def shampoo_instructions(num_cycles): #def function with loop

   if num_cycles < 1:  #using 1st if statement

       print('Too few.')

   elif num_cycles > 4:

       print ('Too many.')

   else:

       i = 0

       while i<num_cycles:

           print (i+1,": Lather and rinse.")

           i = i + 1

       print('Done.')

user_cycles = int(input())

shampoo_instructions(user_cycles)

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Answer:

The c++ program to check prime numbers is shown below.

#include <iostream>

using namespace std;

int main() {

   int num, prime=0;

   do

   {

       cout<<"Enter a positive number."<<endl;

       cin>>num;

       if(num<1)

       {

           cout<<"Invalid number. Enter a positive number"<<endl;

           cin>>num;

       }

   }while(num<1);

   

   if(num==1 || num==2 || num==3)

       cout<<num<<" is a prime number."<<endl;

   else if(num%2 == 0)

       cout<<num<<" is not a prime number."<<endl;

   else

   {

       for(int k=3; k<num/2; k++)

       {

           if(num%k == 0)

               prime++;

       }    

   if(prime>1)

       cout<<num<<" is not a prime number."<<endl;

   else

       cout<<num<<" is a prime number."<<endl;

   }

}

OUTPUT

Enter a positive number.

-7

Invalid number. Enter a positive number

0

Enter a positive number.

79

79 is a prime number.

Explanation:

The user input is validated for positivity. A do while loop along with an if statement is implemented for verification.

do

   {

       cout<<"Enter a positive number."<<endl;

       cin>>num;

       if(num<1)

       {

           cout<<"Invalid number. Enter a positive number"<<endl;

           cin>>num;

       }

   }while(num<1);

The test for prime number is done by using multiple if else statements.

If user inputs 1, 2, or 3, message is displayed.

Else If user inputs an even number, message is displayed for not prime. This is done by taking modulo of the number upon division by 2.

Else if user inputs neither an even number nor a number less than 3, the modulus of the number is taken with divisors beginning from 3 up to half of the input number.

For this, an integer variable prime is initialized to 0. A number can be completely divisible by itself or by its factors.

If the number is divisible by any of the divisors, value of variable prime is increased by 1. If value of prime is greater than 1, this means that the user input is divisible by more than one divisor. Hence, the given number is not a prime number.

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