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damaskus [11]
3 years ago
13

Suppose a researcher is testing the hypothesis Upper H 0​: pequals0.4 versus Upper H 1​: pless than0.4 and she finds the​ P-valu

e to be 0.33. Explain what this means. Would she reject the null​ hypothesis? Why? Choose the correct explanation below. A. If the​ P-value for a particular test statistic is 0.33​, she expects results no more extreme than the test statistic in about 33 of 100 samples if the null hypothesis is true. B. If the​ P-value for a particular test statistic is 0.33​, she expects results no more extreme than the test statistic in exactly 33 of 100 samples if the null hypothesis is true. C. If the​ P-value for a particular test statistic is 0.33​, she expects results at least as extreme as the test statistic in about 33 of 100 samples if the null hypothesis is true. D. If the​ P-value for a particular test statistic is 0.33​, she expects results at least as extreme as the test statistic in exactly 33 of 100 samples if the null hypothesis is true. Choose the correct conclusion below. A. Since this event is​ unusual, she will reject the null hypothesis. B. Since this event is not​ unusual, she will reject the null hypothesis. C. Since this event is​ unusual, she will not reject the null hypothesis. D. Since this event is not​ unusual, she will not reject the null hypothesis.
Mathematics
1 answer:
andre [41]3 years ago
3 0

Answer:

D. If the​ P-value for a particular test statistic is 0.33​, she expects results at least as extreme as the test statistic in exactly 33 of 100 samples if the null hypothesis is true.

D. Since this event is not​ unusual, she will not reject the null hypothesis.

Step-by-step explanation:

Hello!

You have the following hypothesis:

H₀: ρ = 0.4

H₁: ρ < 0.4

Calculated p-value: 0.33

Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

In this case, you have a 33% chance of getting a value as extreme as the statistic value if the null hypothesis is true. In other words, you would expect results as extreme as the calculated statistic in 33 about 100 samples if the null hypothesis is true.

You didn't exactly specify a level of significance for the test, so, I'll use the most common one to make a decision: α: 0.05

Remember:

If p-value ≤ α, then you reject the null hypothesis.

If p-value > α, then you do not reject the null hypothesis.

Since 0.33 > 0.05 then I'll support the null hypothesis.

I hope it helps!

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Answer:

A) a_n = 5n + 2

B) a_n = (2^(n + 1)) - 1

Step-by-step explanation:

A) The sequence is given as;

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The differences are:

5,5,5,5.

This is an arithmetic sequence following the formula;

a_n = a_1 + (n - 1)d

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a_n = a_1 + (n - 1)5

Now, a_1 = 7. Thus;

a_n = 7 + 5n - 5

a_n = 5n + 2

B) The sequence is given as;

{ 3,7,15,31,63,...}​

Now, let's write out the differences of this sequence:

Differences are:

4, 8, 16, 32

This shows that it is a geometric sequence with a common ratio of 2.

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What is the answer need it
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Answer:

\frac{7}{10} |

Step-by-step explanation:

STEP 1:

2/3 + 7/10 = ?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

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Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(\frac{2}{3} * \frac{10}{10}) + (\frac{7}{10} * \frac{3}{3}) = ?

Complete the multiplication and the equation becomes

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The two fractions now have like denominators so you can add the numerators.

Then:

\frac{20+21}{30} = \frac{41}{30}

This fraction cannot be reduced.

The fraction 41/30

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STEP 2:

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Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

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This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 21 and 30 using

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\frac{41}{30} + \frac{-2}{3} =\frac{7}{10}|

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